此解法的时间复杂度是O(log2(n)),空间复杂度是O(1)。 publicintsearch(int[] nums,inttarget) {if(target < nums[0] || target > nums[nums.length-1]) {return-1; }intstart =0,end= nums.length-1;while(start <=end) {intmid = (end+start)/2;if(nums[mid] == target) {returnmid; ...
Premium Easy Topics Companies Given an array of integersnumswhich is sorted in ascending order, and an integertarget, write a function to searchtargetinnums. Iftargetexists, then return its index. Otherwise, return-1. You must write an algorithm withO(log n)runtime complexity. ...
【Leetcode_easy】704. Binary Search problem 704. Binary Search solution: classSolution {public:intsearch(vector<int>& nums,inttarget) {intleft =0, right = nums.size()-1, mid =0;while(left<=right)//errr...{ mid= left + (right-left)/2;if(nums[mid]<target) left = mid+1;elseif...
就往右子树里面找if(root.val<val){returnsearchBST(root.right,val);}// 如果相等,返回当前以节点为根节点的子树if(root.val==val){returnroot;}// 如果val小于当前节点值,就往左子树里面找if(root.val>val){returnsearchBST(root.left,val);}
Given a non-empty binary search tree and a target value, find the value in the BST that is closest to the target. Note: Given target value is a floating point. You are guaranteed to have only one unique value in the BST that is closest to the target. ...
首发于一行Python刷LeetCode 切换模式写文章 登录/注册 [Binary Search]35.Search Insert Position(Easy) 水木 人工智能,区块链,币圈,互联网爱好者题目如下: 代码: return bisect.bisect_left(nums, target)编辑于 2018-10-13 11:07 内容所属专栏 一行Python刷LeetCode 追求用最精简的python代码解决LeetCode题目(...
今天的笔记包含基于改造二分法(Modified Binary Search)类型下的7个题目,它们在leetcode上的编号和题名分别是: 704 - 二分查找 74 - 搜索二维矩阵 33 - 搜索旋转排序数组 81 - 搜索旋转排序数组 II 153 - 寻找旋转排序数组中的最小值 162 - 寻找峰值 ...
After a lot of practice in LeetCode, I've made a powerful binary search template and solved many Hard problems by just slightly twisting this template. I'll share the template with you guys in this post.I don't want to just show off the code and leave. Most importantly...
大家可以看完讲义结合 LeetCode Book 二分查找练习一下 问题定义 给定一个由数字组成的有序数组 nums,并给你一个数字 target。问 nums 中是否存在 target。如果存在, 则返回其在 nums 中的索引。如果不存在,则返回 - 1。 这是二分查找中最简单的一种形式。当然二分查找也有很多的变形,这也是二分查找容易出错...
packageleetcode.easy;/** * Definition for a binary tree node. public class TreeNode{int val; TreeNode * left; TreeNode right; TreeNode(int x){val = x;}}*/publicclassLowestCommonAncestorOfABinarySearchTree{publicTreeNodelowestCommonAncestor1(TreeNoderoot,TreeNodep,TreeNodeq){// Value of cu...