result[level-1].push_back(root->val); travel(root->left,result,level+1); travel(root->right,result,level+1); } }; Title: Given a binary tree, return thezigzag level ordertraversal of its nodes' values. (ie, from
intlv)8:treeNode(node), level(lv){}9};10public:11vector<vector<int>> levelOrder(TreeNode*root) {12queue<Node>nodeQueue;13vector<vector<int>>ret;14if(root ==NULL)15returnret;16nodeQueue.push(Node(root,0));17intdep = -1;18while(!nodeQueue.empty()){19Node node ...
Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree [3,9,20,null,null,15,7], 代码语言:javascript 代码运行次数:0 运行 AI代码解释 3/\920/\157 return its level order traversal as: 代码...
return its bottom-up level order traversal as: [ [15,7], [9,20], [3] ] 1. 2. 3. 4. 5. 分析: 这道题目跟上道题目很相似 Leetcode: Binary Tree Level Order Traversal ,唯一不同的就是返回结果是从子叶节点到根节点,所以我们只需要将结果翻转下就好了! 参考代码: /** * Definition for ...
leetCode 107. Binary Tree Level Order Traversal II 二叉树层次遍历反转,107.BinaryTreeLevelOrderTraversalIIGivenabinarytree,returnthe bottom-uplevelorder traversalofitsnodes'values.(ie,fromlefttoright,levelbylevelfromleaftoroot).For
Can you solve this real interview question? Binary Tree Level Order Traversal - Given the root of a binary tree, return the level order traversal of its nodes' values. (i.e., from left to right, level by level). Example 1: [https://assets.leetcode.c
1. Problem Descriptions:Given two integer arrays inorderandpostorderwhereinorderis the inorder traversal of a binary tree andpostorderis the postorder traversal of the same tree, construct and retu…
这道题和LeetCode笔记:107. Binary Tree Level Order Traversal II是姊妹题,解题思路都是一样的,只是结果要求的顺序是反的,同样有两种方法,也就是经常说到的DFS深度优先遍历和BFS广度优先遍历。 BFS: 广度优先遍历就是一层层地攻略过去,把每一层的所有节点都记录下来再走向下一层。因为每层会有多个节点,不是简...
Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree [3,9,20,null,null,15,7], 3 / 9 20 / 15 7 return its level order traversal as: ...
Level order(Breath-first Search) leetcode: 144, 94, 145 Tree structNode{Node*left;Node*right;intdata;};Node*root=...;// 假設已經建立二元樹了 Preorder // preorder traversalvoidtraversal(Node*p){if(!p)return;cout<<p->data;// 先輸出樹根traversal(p->left);// 次輸出左子樹traversal(p-...