翻译过来是，非法的操作数，为二元操作符/，int *和int 意思是，int */int这种除法操作是不合法的。出错的一行是p=(p1+p2)/2，不知道指针除以2是要做什么呢？p=(p1+p2)/2; 地址与地址不能相加p = (p2 - p1)/2 + p1 就行了
c报错 invalid operands of types 'double' and 'double()(double)' to binary 'operator/'是怎么回事啊快原分边完性受团的想备double mutual(double a,double b,double f)快原分边完性受团的想备{快原分边完性受团的想备double y;快原分边完性受团的想备y=(-(b*a+f*(1-a))*log(b*a+f*(...
纯语法错误，scanf("%f%f%f",&a&b&c); 改成 scanf("%f%f%f",&a, &b, &c); 就可以了。
static BinaryLogicalOperator valueOf(String name) Returns the enum constant of this type with the specified name. static BinaryLogicalOperator[] values() Returns an array containing the constants of this enum type, in the order they are declared. Methods inherited from class java...
error: invalid operands of types 'int' and '<unresolved overloaded function type>' to binary 'operator<<' cout << a&&b <<endl错误 cout << a&&b <<endl这一行出现了这个错误 查了下是因为运算符优先级的问题,加个()就行了 cout << (a&&b) <<endl...
scanf("%i"&po); 这个输入语句参数间少个逗号，加上逗号就好：scanf("%i",&po); //参数之间加逗号 还有后面那个判断，把"=="写成"="了，常见错误 if (po =1)改成 if (po ==1)哦，还有：printf("你会发现，序列最终会变成4，2，1，4，2，1的循环，是不是很神奇？");//return 0...
mutual.c:7:error:invalid operands of types ‘double’ and ‘double ()(double)’ to binary ‘operator/’mutual.c:In function ‘double givenmutual(double,double,double,double,double,double,double,double)’:mutual.c:15:error:invalid operands of types ‘double’ and ‘double ()(double)’ to ...
定义数组的时候，是有大小限制的，不是随意定义的。像这种定义方式 int a[10000][10000];都是在栈上分配的，栈的空间不是无限大的，它只占计算机内存中的很小的一部分。你定义的数组所占用的空间，超出了可定义的范围，所以报错了。
15.17 Multiplicative Operators15.18 Additive Operators15.19 Shift Operators15.20 Relational Operators15.21 Equality Operators15.22 Bitwise and Logical Operators15.23 Conditional-And Operator &&15.24 Conditional-Or Operator || Since: 1.6 Nested Class Summary Nested classes/interfaces declared in interface com.sun....
A binary delta operator that instructs the applyDelta(com.tangosol.io.ReadBuffer, com.tangosol.io.ReadBuffer) method to extract bytes from the old value and append them to the new value. The format is the one-byte OP_EXTRACT indicator followed by a packed int offset and packed int length...