I want to show that this is uniformly continuous on N. (N is the set of natural numbers, Q the rationals). My first thought was to use induction. Since every point in N is an isolated point, then f is continuous on N. Let N1=[1,a_1], where a_1 is a natural number... ...
Baxter numbers are known to count several families of combinatorial objects, all of which come equipped with a natural involution. In this paper, we add a combinatorial family to the list, and show that the known bijections between these... K Dilks 被引量: 6发表: 2015年 Polynomial endomorph...
If Q is the set of all rational numbers, and f:Qto Q is defined by f(x)=5x+4,AAx in Q, show that f is a bijection.
It is shown in this note that every invertible polynomial transformation of of degree two has a rational inverse defined on the whole space . The same is true for polynomial transformations of higher degrees, satisfying some differential condition which is a real analogue of Jagžev's condition...