//the target amount of water or not if(curr.j1 == target || curr.j2 == target){ if(curr.j1 == target){ //If in our current state, jug1 holds the //required amount of water, then we empty the jug2 //and push it into our path. curr.path.add(new Pair(curr.j1,0)); } ...
365. Water and Jug Problem (GCD or BFS) TBC https://leetcode.com/problems/water-and-jug-problem/description/ -- 365 There are two methods to solve this problem : GCD(+ elementary number theory) --> how to get GCF, HCD, BFS Currently, I sove this by first method 1. how to comput...
复制 importcollectionsclassSolution:defcanMeasureWater(self,x:int,y:int,z:int)->bool:# 首先处理几种极端情况ifz<0or x+y<z:returnFalse #BFSqueue=collections.deque([(0,0)])#建立queue,collections.deque是双端队列,支持从两端添加和删除元素 visited={(0,0)}#建立visitedwhilelen(queue):# current...
You have two jugs, A and B, and an infinite supply of water. There are three types of actions that you can use: (1) you can fill a jug, (2) you can empty a jug, and (3) you can pour from one jug to the other. Pouring from one jug to the other stops when the first jug...
In the three jugs problem, a path from the start node to any node with 6 liters of water in one jug represented a solution to the riddle. In a social network, a path might show us how two people are connected, and the length of the shortest path between two people might tell us ...
There are three jugs with a volume of a, b and c liters. (a, b, and c are positive integers not greater than 200). The first and the second jug are initially empty, while the third is completely filled with water. It is allowed to pour water from one jug into another until eithe...