bool DFSKK[105];//DFS的标记 void DFS(int del, int now) { if(del == 0)return; if(now == B) { DFSK = 1; return ; } vector<int>::iterator it; for(it = ver[now].begin() ; it!= ver[now].end() ; it++) { if((*it) != del && !DFSKK[*it]) { DFSKK[*it] = ...
Given a diagram of Farmer John's field, determine how many ponds he has. 输入 * Line 1: Two space-separated integers: N and M * Lines 2..N+1: M characters per line representing one row of Farmer John's field. Each character is either 'W' or '.'. The characters do not have sp...
Iterative Implementation of BFS The non-recursive implementation of BFS is similar to thenon-recursive implementation of DFSbut differs from it in two ways: It uses aqueueinstead of astack. It checks whether a vertex has been discovered before pushing the vertex rather than delaying this check u...
Pattern Used: 🌲 DFS ❓: Given the root of a binary tree, return the maximum path sum of any path. A path is a collection of nodes that are connected by edges, where no node is connected to more than two other nodes. The path must contain at least one node & does not need to...
Given a diagram of Farmer John's field, determine how many ponds he has. Input * Line 1: Two space-separated integers: N and M * Lines 2..N+1: M characters per line representing one row of Farmer John's field. Each character is either 'W' or '.'. The characters do not have ...
('.'). Farmer John would like to figure out how many ponds have formed in his field. A pond is a connected set of squares with water in them, where a square is considered adjacent to all eight of its neighbors. Given a diagram of Farmer John's field, determine how many ponds he ...
解题思路:从任意的W开始,不停把邻接的部分用'.'代替。1次dfs后与初始的这个W连接的所有W就都被替换成了'.',因此知道图中不在出现'W'为止,总共进行dfs的次数就是最后的答案了,8个方向对应8种状态转移,每个格子作为dfs的参数之多被调用一次,所以复杂度为O(8*n*m)=O(n*m)。
{//Create a graph given in the above diagramGraph g(4); g.addEdge(0,1); g.addEdge(0,2); g.addEdge(1,2); g.addEdge(2,0); g.addEdge(2,3); g.addEdge(3,3); cout<<"Following is Breadth First Traversal"<<"(starting from vertex 2) \n"; ...
Given a diagram of Farmer John's field, determine how many ponds he has. Input * Line1: Two space-separated integers: N and M* Lines2..N+1: M characters per line representing one row of Farmer John's field. Each character is either'W'or'.'. The characters do not have spaces betw...
Prime Ring Problem hdu-1016 DFS 摘要:A ring is compose of n circles as shown in diagram. Put natural number 1, 2, ..., n into each circle separately, and the sum of numbers in two adjacen阅读全文 posted @2017-09-05 23:19小小超plus阅读(106)评论(0)推荐(0)编辑 ...