Say you have an array for which theith element is the price of a given stock on dayi. Design an algorithm to find the maximum profit. You may complete at mosttwotransactions. Note: You may not engage in multiple transactions at the same time (ie, you must sell the stock before you ...
Leetcode-Best Time to Buy and Sell Stock -java 题目: Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to f...
问题https://leetcode-cn.com/problems/best-time-to-buy-and-sell-stock-ii/ 练习使用JavaScript解答 /** * @param {number[]} prices * @return {number} */ var maxProfit = function(prices) { if(prices.length < 2) return 0; var arr = []; var i,j,tmp,tmpM; arr[price...
https://leetcode.com/problems/best-time-to-buy-and-sell-stock-ii/ 因为可以进行无限次交易,并且在下一次buy之前必须已经sell。所以只需要把所有price曲线价格上涨的部分加起来就行。 class Solution(object): def maxProfit(self, prices): """ :type prices: List[int] :rtype: int """ maxprofit = 0...
Can you solve this real interview question? Best Time to Buy and Sell Stock - You are given an array prices where prices[i] is the price of a given stock on the ith day. You want to maximize your profit by choosing a single day to buy one stock and choo
121. 买卖股票的最佳时机 - 给定一个数组 prices ,它的第 i 个元素 prices[i] 表示一支给定股票第 i 天的价格。 你只能选择 某一天 买入这只股票,并选择在 未来的某一个不同的日子 卖出该股票。设计一个算法来计算你所能获取的最大利润。 返回你可以从这笔交易中获取的
int sell = 0; int day= 0; while(day<prices.size()){ if(prices[day]<buy) { buy =prices[day]; } sell = max(prices[day]-buy,sell); day++; } return sell; } }; 展开全部 2 回复 dp小亡子 来自 北京 2025.04.19 保证一个最小值,有比他小的就更新 ...
【leetcode】45-best-time-to-buy-and-sell-stock-with-cooldown 力扣 714. 买卖股票的最佳时机包含手续费 开源地址 为了便于大家学习,所有实现均已开源。欢迎 fork + star~ https://github.com/houbb/leetcode 122. 买卖股票的最佳时机 II 给你一个整数数组 prices ,其中 prices[i] 表示某支股票第 i 天...
Best Time to Buy and Sell Stock IV中是求某个给定k次交易的最大收益,和Maximum Subarray III完全一样 本题由于是可以操作任意次数,只为获得最大收益,而且对于一个上升子序列,比如:[5, 1, 2, 3, 4]中的1, 2, 3, 4序列来说,对于两种操作方案: 1 在1买入,4卖出 2 在1买入,2卖出同时买入,3卖出...
If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit. 双指针法 复杂度 时间O(N) 空间 O(1) 思路 根据买卖股票的特性,我们必须先低价买,再高价卖,这个找最大收益的过程实际上是找到目前为...