例如" 1️⃣ 0️⃣ 6️⃣ ✋"是将106放入accumulator1中。 defload(self):num=0ifself.rom[self.instruction_pointer]==' ':acc=1elifself.rom[self.instruction_pointer]==' ':acc=2else:raiseRuntimeError('Unknown instruction {} at position {}'.format(self.rom[self.instruction_pointer...
View Code F 设计算到x时,答案是ans,于是计算x后,ans=(ans*10i+x)%m,其中i为x的位数,然后发现这个可以矩阵转移,对于位数相同的数字,转移的矩阵是相同的,于是分位数转移至多18次即可,复杂度O(27logBLlgBL)。 View Code result:rank5 rating+=65 now_rating=2020,ABC为什么performance上限要设2400?就涨了...
Minik8s CTF This mini CTF is just a selection of what have I seen during some Kubernetes CTFs I participated in. These flags are designed to highlight the use of the kdigger tool and are beginner-friendly. For now, it's only composed of 3 challenges. This challenge could potentially run...
Capture The Flag (CTF) Competitions Cybersecurity Labs and Practice Environments Security Research Resources Contributing Introduction Welcome to the Ultimate Cybersecurity Mastery Roadmap! This comprehensive guide is designed to help you navigate the complex world of cybersecurity, providing a clear path ...
View Code E 将每条限制视为一条边即可,然后预处理k个点到其他点的最短距离,然后状压DP即可 View Code F 签到,树状数组裸题 小号打的,45min不到AK才rank105,好在performance=2400满了,rating+=234,now rating=1627
BEGINNER.Reports on the growing popularity of skiing in Liaoning, China.EBSCO_AspBeijing Review
int main() { ios_base::sync_with_stdio(false), cin.tie(0); int a, b; cin >> a >> b; a = a + b; if (a >= 15 && b >= 8) cout << 1; else if (a >= 10 && b >= 3) cout << 2; else if (a >= 3)
If the examples above looked like illegical ancient Greek codices to you, don’t fret! You can gain quick Linux knowledge from a hacker point of view by playing easy, fun CTF games like OverTheWire’s Bandit:https://overthewire.org/wargames/bandit/. ...
CTFlearn: RSA BEGINNER 原题: RSA BEGINNER 90 points 182solves Cryptography Hard intelagent I found this scribbled on a piece of paper. Can you make sense of it? https://mega.nz/#!zD4wDYiC!iLB3pMJElgWZy6Bv97FF8SJz1KEk9lWsgBSw62mtxQg...
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