已知行列式\(D=\left|\begin{array}{cccc}{1} & {2} & {3} & {5} \\ {2} & {1} & {2} & {1} \\ {1} & {4} & {0} & {5} \\ {10} & {-2} & {1} & {3}\end{array}\right|\),其中\(A_{i j}\) 表示\(D\) 的第\(i\) 行第\(j\) 列元素的代数余...
原式=10a-5b-12a+4b-4+4a-3b- \dfrac {1}{2} =2a-4b- \dfrac {9}{2} 由题意得, 3b-2=0 2a-b-3=0 \cdots a= \dfrac {11}{6} b= \dfrac {2}{3} 当a = \dfrac {11}{6} , b = \dfrac {2}{3} 时 原式 =2 \times \dfrac {11}{6}-4 \times \dfrac {2...
\begin{array}{r},\begin{array}{l},\begin{array}{c} r:righty = \left\{ \begin{array}{rr}a & 12345\\b+x & 78\\l &910\end{array} \right.y={a12345b+x78l910y = \left\{ \begin{array}{rr}a & 12345\\b+x & 78\\l &910\end{array} \right.y=⎩⎨⎧ab+xl...
Answer to: Given this data use regression to find an exponential function. \begin{array}[cccccc] x & 2 & 5 & 7 & 10 & 12 \\ y & 5.4 & 146 & 1312 &...
若随机变量 的分布律为 \begin{array}{c|cccc}X&1&2&4&5\\\hline p_k&0.1&0.2&0.3&0.4\end{array} 则 ( ) A.0.1 B.0.3 C.0.5 D.0.9 你可能感兴趣的试题 多项选择题 下列哪些是清明节的活动( ) A.扫墓 B.插茱萸 C.踏青 D.荡秋千 ...
考虑如下修改过的正交投影矩阵:\( \left( \begin{array}{cccc} \frac{2}{r-l} & 0 & 0 & -\frac{r+l}{r-l}\\ 0 & \frac{2}{t-b} & 0 & -\frac{t+b}{t-b}\\ 0 & 0 & \mathbf{\frac{2}{f-n}} & -\frac{f+n}{f-n}\\ 0 & 0 & 0 & 1 \end{array} \right) ...
\begin array cccccccc } & { -2 - 0 - 0 - 0 = 0 -2 - 0 - 0 = 0 \hline 0 - 0 - 0 - 0 - 00 0 - 0 - 0 - 0 - 0 = 0 - 0 = 0 . . . . . . 0 = 0 = 0 相关知识点: 试题来源: 解析 【解析】 根据晶胞结构分析可知:晶体是由 XeF_{2} 分子通过分子间...
("my combofilter", buf, IM_ARRAYSIZE(buf), hints, IM_ARRAYSIZE(hints), s) ) {puts( buf );}}*/#pragmaoncestructComboFilterState{intactiveIdx;//Index of currently 'active' item by use of up/down keysboolselectionChanged;//Flag to help focus the correct item when selecting active item...
The bases may be used to span both spaces, completely. Answer and Explanation: $$\left ( \begin{array}{cccc} 1&3&2&-4\\ 2&6&1&4\\ -1&-3&1&-8 \end{array} \right ) $$ The basis for the column space of A may be obtained....
Given the following table of values of f(x,y): \begin{array}{cccccc} & & & y & & \ & & 0 & 10 & 20 & 30 \ & 0 & 100 & 110 & 120 & 130 \ x & 0.1 & 97 & 106 & 115 & 124 \ & 0.2...