Basic Calculator 2 Implement a basic calculator to evaluate a simple expression string. The expression string contains only non-negative integers, +, -, *, / operators and empty spaces . The integer division should truncate toward zero. You may assume that the given expression is always valid. ...
Basic Calculator 基本计算器-Leetcode 1.题目: Implement a basic calculator to evaluate a simple expression string. The expression string may contain open(and closing parentheses), the plus+or minus sign-, non-negative integers and empty spaces . You may assume that the given expression is always...
Implement a basic calculator to evaluate a simple expression string. The expression string may contain open(and closing parentheses), the plus+or minus sign-, non-negative integers and empty spaces. You may assume that the given expression is always valid. Some examples: "1 + 1" = 2 " 2-...
Implement a basic calculator to evaluate a simple expression string. The expression string may contain open(and closing parentheses), the plus+or minus sign-, non-negative integers and empty spaces. You may assume that the given expression is always valid. Some examples: "1 + 1" = 2 " 2-...
Problem Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . The expression string contains only non-negative integers, +, -, *, / operator...
1 // The main idea of this is the left bracket might change the sign of a number, however, this does not seem to be very generalized 2 // https://leetcode.com/problems/basic-calculator/discuss/62362/JAVA-Easy-Version-To-Understand!!! 3 public class Solution { 4 // 1-2-(4+5+2...
这道题就是最经典的字符串表达式的计算问题,可以先做中序转后序,然后去计算。 代码如下: import java.util.Stack; /* * 我的做法是中序转后序 * 然后在计算 * */ public class Solution { public int calculate(String s) { if(s==null || s.length() == 0) ...
Code: importjava.util.Scanner;publicclassSimpleCalculatorIfElse{public static void main(String[]args){//Create a ScannerobjectforinputScanner scanner=new Scanner(System.in);//Input first number System.out.print("Enter the first number: ");double num1=scanner.nextDouble();//Input second number ...
java 考点: 模拟 题解: 使用栈模拟即可,遇到右括号时,一直运算到出现左括号,当遇到运算符时,需要进行判断,当前c的优先级不高于栈顶就进行运算。 publicclassSolution{/** *@params: the expression string *@return: the answer */publicintcalculate(String s){// Write your code hereif(s ==null|| s....
227. Basic Calculator II Implement a basic calculator to evaluate a simple expression string. The expression string contains only non-negative integers, +, -, *, / operators and empty spaces . The integer division should truncate toward zero....