Implement a basic calculator to evaluate a simple expression string. The expression string may contain open(and closing parentheses), the plus+or minus sign-, non-negative integers and empty spaces. You may assume that the given expression is always valid. Some examples: "1 + 1" = 2 " 2-...
Basic Calculator 2 Implement a basic calculator to evaluate a simple expression string. The expression string contains only non-negative integers, +, -, *, / operators and empty spaces . The integer division should truncate toward zero. You may assume that the given expression is always valid. ...
Implement a basic calculator to evaluate a simple expression string. The expression string contains only non-negative integers,+,-,*,/operators and empty spaces. The integer division should truncate toward zero. You may assume that the given expression is always valid. Some examples: "3+2*2" ...
Code: importjava.util.Scanner;publicclassSimpleCalculatorIfElse{public static void main(String[]args){//Create a ScannerobjectforinputScanner scanner=new Scanner(System.in);//Input first number System.out.print("Enter the first number: ");double num1=scanner.nextDouble();//Input second number S...
import java.util.Stack; /** * https://leetcode.cn/problems/basic-calculator-ii/ * * 给你一个字符串表达式 s ,请你实现一个基本计算器来计算并返回它的值。 * 整数除法仅保留整数部分。 * 你可以假设给定的表达式总是有效的。所有中间结果将在 [-2³¹, 2³¹ - 1] 的范围内。 * 注意...
Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . The expression string contains only non-negative integers, +, -, *, / operators , op...
Note: Do not use the eval built-in library function. 这道题就是最经典的字符串表达式的计算问题,可以先做中序转后序,然后去计算。 代码如下: import java.util.Stack; /* * 我的做法是中序转后序 * 然后在计算 * */ public class Solution ...
1 // The main idea of this is the left bracket might change the sign of a number, however, this does not seem to be very generalized 2 // https://leetcode.com/problems/basic-calculator/discuss/62362/JAVA-Easy-Version-To-Understand!!! 3 public class Solution { 4 // 1-2-(4+5+2...
java 精选的答案无法处理负数情况,需要添加负数的判断。 1. 第一个数字就是负数 2. 括号里的第一个数字是负数 这个代码是根据lc上的讨论 添加了一个判断。 classSolution{publicintcalculate(String s) {if(s ==null|| s.length() ==0)return0; Stack<Integer> nums =newStack<>(); Stack<Character> ...
Implement a basic calculator to evaluate a simple expression string. The expression string contains only non-negative integers, +, -, *, / operators and empty spaces . The integer division should truncate toward zero. You may assume that the given expression is always valid. ...