(BASH_ARGC[i])); then args=("${BASH_ARGV[@]:iarg:BASH_ARGC[i]}") ble/array#reverse args args=" ${args[*]}" ((iarg+=BASH_ARGC[i])) else args= fi message="$message @ ${BASH_SOURCE[i]}:${BASH_LINENO[i-1]} (${FUNCNAME[i]}$args)$nl" done ble/util/put "$message...
So your $ARGV[1] is being seen by the shell and not perl. Next, you don't actually have an ARGV array here because you told perl to read from stdin since you're using -n: $ perl -le 'print "$ARGV[0]"' foo foo $ perl -nle 'print "$ARGV[0]"' foo $ You can either us...
linux Bash中的Argc和Argv [duplicate]定义一个变量：ARGC=$# 你的if语句就像
这个时候 bash 程序的 argv[0] 是“bash”,但 $0 却是 “foo”。也就是说如果 -c 选项的参数后面还有参数,那么那些参数会依次成为 $0(覆盖了旧的值 argv[0])、$1、$2...。 bash /a/b/c.sh cat foo.sh echo $0 bash foo.sh foo.sh bash ./foo.sh ./foo.sh ./foo.sh ./foo.sh 这个时...
C语言 如何在bash中为main传输argv重定向操作符与参数不同。实际上，重定向操作符将给定文件的内容移动...
bash-complete-partial-path 通过添加不完整的路径展开（类似于 Zsh）来增强 Bash（它在 Linux 上，...
I have a file (test.py) that receives sys.argv from the console/bash: import sys def main(): ans = int(sys.argv[1])**int(sys.argv[1]) with open('test.out', 'w') as fout: fout.write(str(ans)) if __name__ == '__main__': main() Usually, I could just do $ pyth...