# let a = a+10 bash: let: =: syntax error: operand expected (error token is "=") 自加操作let no++ 自减操作let no-- 简写形式let no+=10,let no-=20,分别等同于let no=no+10,let no=no-20 # a=1; while (( $a < 5 )); do echo $a; let a++; done 1 2 3 4编辑...
myscript.sh: line 45: {"json":"coming-back-from-server"}0") myscript.sh: line 49: {"json":"coming-back-from-server"}1 > 1 : syntax error: operand expected (error token is "{"json":"coming-back-from-server"}1 > 1 ") myscript.sh: line 45: {"json":"coming-back-from-serv...
后缀自增/减运算和赋值(如:+=, -=, *=, /=等等)时,涉及变量的时候不要将变量展开,否则会报错。 [root@c7-server ~]# declare -i i=1[root@c7-server ~]# (($i++))-bash: ((:1++: syntax error: operand expected (error token is"+") [root@c7-server ~]# (($i+=1))-bash: ((:...
[root@chinadaas109 ~]# let c=$a + $b -bash: let: +: syntax error: operand expected (error token is "+") [root@chinadaas109 ~]# let c=$a+$b [root@chinadaas109 ~]# echo $c 7 1. 2. 3. 4. 5. 6. 7. eg: 给脚本传递两个参数(整数); 显示此两者之和,之乘积; #!/bin/...
./1.1test: line 2: +: syntax error: operand expected (error token is " ") the tenth param is the elevnth param is the total is 我们不输入任何命令行参数,则脚本无法执行。 所以,我们可以通过-n这个参数进行检测: [root@wzp ~]# cat 1.2test ...
linux bug 在$取值的时候,括号里面只需要跟变量即可(变量可自行进行计算),不需要对括号内进行运算的变量在进行取值操作ss syntax error :operand expected(error)遇到这个错误 操作 #!/bin/bash read $1 b= ((b%2)) if [ $a=0 ] echo “偶数”...
我想使我的bash脚本更容易阅读。为此,我想引用位置参数来命名它们。我试过了declare -n time="\$1"但这不起作用。我收到了错误信息,declare: $1: syntax error: operand expected (error token is "$1")有人有解决办法或建议,请告诉我。
-bash: test: test: binary operator expected $ [[ -n "test string" ]]; echo $? 0 $ [[ -n test string ]] -bash: syntax error in conditional expression -bash: syntax error near 'string' 可以看到,value变量对应的字符串带有空格,[[ -n $value ]]命令可以正确判断到value变量值不是空字符...
问bash:语法错误:需要操作数(错误标记为"-")EN使用HBuilderX开发uni-app遇见这个问题 ``` if (!('^[1][3,4,5,6,7,8,9][0-9]{9}$'.test(this.account))) { uni.showToast({ icon: 'none', title: '请输入正确的手机号码' }); return; } ``` ...
A Bash If Statement takes a command and will test the exit code of that command, using the syntax if ; then ; fi. Unless you expect to use the value of the exit code of your command, do not use the exit status code using $?, it is unnecessary and can be error-prone when used ...