Taken fromBash shell script split array: 从Bash shell脚本拆分数组: IN="bla@some.com;john@home.com" arrIN=(${IN//;/ }) Explanation: 解释: This construction replaces all occurrences of';'(the initial//means global replace) in the stringINwith' '(a single space), then interprets the s...
https://linuxhandbook.com/bash-split-string/ #!/bin/bash # # Script to split a string based on the delimiter my_string="One;Two;Three" my_array=($(echo $my_string | tr ";" "\n")) #Print the split string for i in "${my_array[@]}" do echo $i done Output One Two Three ...
Method 2: Split string using tr command in Bash This is the bash split string example using tr (translate) command: #!/bin/bash # # Script to split a string based on the delimiter my_string="Ubuntu;Linux Mint;Debian;Arch;Fedora" my_array=($(echo $my_string | tr ";" "\n")) #...
split() { local string="$1" local delimiter="$2" if [ -n "$string" ]; then local part while read -d "$delimiter" part; do echo $part done <<< "$string" echo $part fi } Run Code Online (Sandbox Code Playgroud) 例如,命令 $ split 'a;b;c' ';' Run Code Online (Sandbox...
我在循环中打印它时只得到第一个字符串,没有括号围绕$IN它起作用。 答案 您可以设置内部字段分隔符(IFS)变量,然后将其解析为数组。当在命令中发生这种情况时,对IFS的分配仅发生在该单个命令的环境中(要read)。然后它根据IFS变量值将输入解析为一个数组,然后我们可以迭代它。
Bash 编程高级教程(全) 原文:Pro Bash Programming 协议:CC BY-NC-SA 4.0 一、你好世界:你的第一个 Shell 程序 一个 shell 脚本是一个包含一个或多个您可以在命令行上输入的命令的文件。本章描述了如何创建这样的文件并使其可执行。它还涵盖了围绕 she
The output shows the first element of theip_array. The script below uses thecutcommand to extract a substring. The-doption specifies the delimiter to use to divide the string into fields and the-foption sets the number of the field to extract. ...
echo "Bash Array Of Strings" | awk '{split($0,a," "); print a[2]}' # Output: # 'Array' In this example, we used awk to split a string into an array. Thesplitfunction in awk divides the string into an arrayausing space as the delimiter. We then printed the second element of...
Split a string on a delimiterCAVEAT: Requires bash 4+This is an alternative to cut, awk and other tools.Example Function:split() { # Usage: split "string" "delimiter" IFS=$'\n' read -d "" -ra arr <<< "${1//$2/$'\n'}" printf '%s\n' "${arr[@]}" }...
csv 将Bash数组转换为分隔字符串你把arrayids通过一个空格合并后的字符串构建转移到一个类型为string的新...