By turning a block of code into a heredoc and redirect it to the dummy command ‘:’, we’ve essentially prevented the block of code from executing. We’ve enclosedthe delimiter token to escape all the special characters in the content.This is done to prevent any command substitution from ...
3.1.2.1 Escape Character A non-quoted backslash ‘\’ is the Bash escape character. It preserves the literal value of the next character that follows, with the exception ofnewline. If a\newlinepair appears, and the backslash itself is not quoted, the\newlineis treated as a line continuatio...
This prevents reinterpretation of all special characters within the quoted string -- except $, ` (backquote), and \ (escape). Keeping $ as a special character within double quotes permits referencing a quoted variable ("$variable"), that is, replacing the variable with its value man bash 写...
Single quotes in bash will suppress special meaning of every meta characters. Therefore meta characters will be read literally. It is not possible to use another single quote within two single quotes not even if the single quote is escaped by backslash. #!/bin/bash #Declare bash string variabl...
All the single-character shell options documented in the description of the set builtin command can be used as options when invoking bash.The following options are also available:-c string If the -c option is present, then commands are read from string. If there are arguments after the ...
When referencing a variable, it is generally advisable to enclose its name in double quotes. This prevents reinterpretation of all special characters within the quoted string -- except $, ` (backquote), and \ (escape).引自Whole 2013-09-13 18:33:01 回应 ...
Mostly, system admins would like to add some color to their dull shell prompt. This can be achieved with the help of ANSI escape sequences in the PS1 variable. These escape sequences need to be enclosed in \[ and \] in order to work properly. In a simple way we can use this comma...
Interestingly, we can disable variable interpolation inside double quotes as well, if we use the \ escape character as a prefix to $: $ msg="Hello \$USER" $ echo $msg Hello $USERCopy Again, as we anticipated, Bash printed the literal value of the string and no variable interpolation occu...
Learn how to escape characters in Bash on Linux to handle special characters effectively and improve your scripting skills.
will produce the same results as if you surrounded the string with single quotes. To use a literal backslash, just surround it with quotes ('\') or, even better, backslash-escape it (\\). Here is a more practical example of quoting special characters. A few UNIX commands take arguments...