所以BALANCE。用同一个方法 Na2CO3 + 2HCl --->2NaCl +CO2+H2O 你数数左边同右边分别有几个Na，H，Cl 就知。如果 HCl 唔用两个，咁右边就唔够 Cl 俾两个 Na。 希望答到你 (3) 个条chemical equation 系左边有一个PO4 3- 而右边又有一个PO4 3- 所以就balance左 如果由chemical equatio...
NaCl +2HO = Na + HCl + O2 ReactantsProducts Na11✔️ Cl11✔️ H21❌ O22✔️ His not balanced. Add1molecule ofHClto the product (right-hand) side to balance Hydrogen: NaCl +2HO = Na +2HCl + O2 ReactantsProducts ...
Balance this equation. Show my work please. Cr2O7 + H + C2H6O ---> Cr + C2H4O + H2O Balance the following equation: K_2CrO_4 + Na_2SO_3 + HCl to KCl + Na_2SO_4 + CrCl_3 + H_2O. Complete and balance the following equation: HCl(aq) + NaH...
Write the balanced ionic (complete) and net ionic equations for the following reaction. (include the state: aq, s, l, or g) HNO3(aq) + KOH(aq) arrow KNO3(aq) + H2O(l) Complete and balance the following equation. Then writ...
Mn21❌ N24❌ Mnis not balanced. Add1molecule ofMn(NO3)2to the product (right-hand) side to balance Manganese: H2C2O4+2KMnO4+2HNO3=2CO2+2Mn(NO3)2+2KNO3+2H2O2 ReactantsProducts H44✔️ C22✔️ O1826❌ K22✔️
(2)打开B的活塞,A中发生反应:2NaClO3+4HCl=2ClO2↑+Cl2↑+2NaCl+2H2O。 为使ClO2在D中被稳定剂充分吸收,滴加稀盐酸的速度宜 (填“快”或“慢”)。 (3)关闭B的活塞,ClO2在D中被稳定剂完全吸收生成NaClO2,此时F中溶液的颜色不变,则装置C的作用是 。 (4)已知在酸性条件下NaClO2可发生反应生成NaCl并释...
\[\ce{Fe^3+ + 3H2O <=> Fe(OH)3 + 3H+} \]那么:改变条件平衡移动水解程度\(c(\ce{H+})\)\(\ce{pH}\)现象 升高温度 正向移动 增大 增大 降低 颜色变深 加水稀释 正向移动 增大 减小 升高 颜色变浅 加\(\ce{FeCl3}\) 固体 正向移动 减小 增大 降低 颜色变深 加\(\ce{HCl}\) 逆向...
The unbalanced equation is CH4(g) + 2O2(g) gives CO2(g) + 2H2O(g). Balance the equation and classify the reaction as a combination C, decomposition D, combustion CO, single SR, and or double replacement DR. MnO_3+HC...
NaOH (aq) + Fe(NO_3)_3 (aq) to Balance the following equations: a) HCl + CaCO_3 = ? b) HCl + Na_2CO_3 = ? c) HCl + NaOH = ? Balance this equation- Cu(NO3) 2 (aq) + NaOH (aq) →Cu(OH)2 (s) + NaNO3 (aq) Balance the following equation: Na +...
Step 2: Multiply coefficients for compounds to balance out each element For each element that is not equal, try to balance it by adding more of it to the side with less. Sometimes there may be multiple compounds with that element on one side, so you'll need to use your be...