def min(x,y): if x < y: return x else: return y def package(weight, value, n, total): #the items that you can choose :i, i+1, ...,n #the volume of the package:j cur_weight = min(weight[n]-1, total) for j in range(1, weight[n]): m[n][j]=0 for j in range(...
In BackPack I, II, III, IV, the reason that we can use a 1D array is because the 2D array solutiononly uses the previous rows' information, so it is a pure space optimization. BackPack VI is different, it is an 1D dynamicprogramming problem. For a given sum i, we search across the...
【NOTE 2】 If you found any question and problem after receipt the backpack,please contact us for help firstly. 【NOTE 3】 Since this is newly produced, some kind of smell is possible.Please donot worry about it,put the opened backpack in a ventilated and dry place for some times,no fl...
2. Backpack II Givennitems with size Ai and value Vi, and a backpack with sizem. What's the maximum value can you put into the backpack? http://www.lintcode.com/en/problem/backpack-ii/ f[n][m] = max(f[n-1][m], f[n-1][m-A[n]]+V[n]) Normal 2-d array [TO DO] Op...