答案:解析: A为CH3CH(CH3)CH2CHBrCH(CH3)CH3 B2为CH3(CH3)CHCH=CHCH(CH3)CH3 C为CH3CH(CH3)CHO E为(CH3)2C=CH2 导解:B2臭氧化分解后只生成一种C,说明B2的结构对称,C经两步处理后得到有侧链的烯烃E,E的结构只能是(CH3)2C=CH2.练习册系列答案 1...
This document is part of Subvolume A2 `Binary Liquid Systems of Nonelectrolytes, Part 2' of Volume 13 `Vapor-Liquid Equilibrium in Mixtures and Solutions' of Landolt-Börnstein Group IV `Physical Chemistry'. It corresponds to the entry LB5119 of the Print Version and the ELBT Database, re...