洛谷:ARC111F Do you like query problems Atcoder:ARC111F Do you like query problems Problem 给出三个数 n,m,q。 你有一个长度为 n 的序列 a,初始全为为 0,你有三种操作: 操作1:给出 l,r,v,让区间 [l,r] 对v 取min。 操作2:给出 l,r,v,让区间 [l,r] 对v 取max。 操作
可以同 P4389 付公主的背包 用分治乘优化到 \(O(n \log^2 n)\)。 ARC111F Do you like query problems? (3100) 可以对每个位置分别考虑,可以线性得到贡献为关于 \(x=i(n+1-i)\) 的\(q\) 次多项式,但无法避免插值(不过足以通过)。 更聪明的做法,首先对值域将期望拆成概率。枚举 \(w \in [0...
プログラミングを始めて一年ちょい2024年の8月17日に入水しました!嬉しいです。 少しでもこの記事が他の人のお役に立てたらいいなと思います。 入水までの遷移です。 入水までにやったことです。(AtCoder Problemsより) まず水色のレベル感 AtCoderの社長のchokudaiさんの記事です。 https:/...
Also I don't understand the "recycling the same line of insights" part. There are examples of those, but you can't tell me that these kind of problems occur all or even most of the time on Atcoder. → Reply bokunopicolo 9 months ago, # ^ | 0 LMAO how many atcoder problems...
like if we a problems where we don't have any queries. we just have to pass some bridges but the number of bridges can be large(large enough to not bruteforce maybe). How will we solve that version of this problem? → Reply
/*先读懂题:“More specifically, for every non-empty subsequence (not necessarily contiguous) of the string ABCDE, there is a participant named after that subsequence who solved the problems corresponding to the letters in their name and did not solve the other problems.”的意思是:对于字符串 ...
从某种程度上来说,更改了部分思路,和 https://oj.leetcode.com/problems/candy/有点像。 代码语言:javascript 代码运行次数:0 运行 AI代码解释 import java.util.Scanner;public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int count = sc.nextInt()...
There are ways to chooseKvertices from the trees. For each of them, letSbe the set of the chosen vertices, and find the sum off(S) over all ways. Since the answer may be extremely large, print it modulo 924844033(prime). Since it was too easy for him, he decided to solve this p...
ATCoder contests are typically composed of several problems that need to be solved individually. Participants are given a set amount of time to solve as many problems as they can. Each problem has a predetermined point value, and contestants' final rankings are determined by their total accumulat...
链接:A - Thermometer 签到题 #include <bits/stdc++.h> using namespace std; double x; int main(){ ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); cin >> x; if (x >= 38.0) { cout << 1; return 0; } else if (x >= 37.5) { ...