3.AtCoder DP Contest 速通指南2024-10-23 收起 题单链接 这是AT 之前办的一场 DP 专题,里面都是很经典的问题,可以帮助大家复习 DP 的套路,个人感觉对于巩固基础来说质量很高,建议大家去去练习一下,尽量不要看题解。 本博客只讨论了绿色及以上难度的题目,下面是我的题解。 I Coins 设fi,j 表示扔到了...
no-stack-protector,unroll-loops,fast-math") // #pragma GCC target("sse,sse2,sse3,ssse3,sse4.1,sse4.2,avx,avx2,popcnt,tune=native") #define isPbdsFile #ifdef isPbdsFile #include <bits/extc++.h> #else #include <ext/pb_ds/priority_queue.hpp> #include <ext/pb_ds/hash_policy.hpp...
https://atcoder.jp/contests/abc155/tasks/abc155_e I found this dp solution, am unable to understand what does dp state denote and how transitions are made?https://atcoder.jp/contests/abc155/submissions/10154214 Or any other solution?
In general, DP problems can often be thought of as a decision making process, where you make some "local" decision and your state after that local decision becomes some state you have previously calculated the answer for. So, when you are on a given state, you try all the local decisions...
AtCoder Beginner Contest 180 个人题解(快乐DP场) Here A - box 输出\(N - A + B\) B - Various distances 按题意输出 3 种距离即可 #include <bits/stdc++.h> using namespace std; using ll = long long; int main() { ios_base::sync_with_stdio(false), cin.tie(0);...
AtCoder Beginner Contest 235 F(数位dp) 严格鸽 Educational Codeforces Round 177 (Rated for Div. 2) D(组合数) 没想到吧,我更新了( XCPC萌新算法互助进步群2️⃣:174495261 题意您想构造一个字符串 s ,由小写的拉丁字母组成,以使以下条件保持:对于每对索引 i 和 j ,使得 s_{i} = s_{j} ,...
很明显是个dp,我们用 f[i] 表示前 i 个数有多少种不同的序列。 f[i] 可以由 f[i−1] 转移而来 1)直接在 f[i - 1] 种不同的序列后面添上a[i]2)f[i - 1] 种不同的序列中的最后一个和a[i]合并 如果没有意外的话, f[i]=2∗f[i−1] 就可以了。 但是考虑到某些情况下会产生重叠...
Atcoder Grand Contest 030 F - Permutation and Minimum(DP),洛谷题面传送门&Atcoder题面传送门12天以前做的题了,到现在才补/yun做了一晚上+一早上终于AC了,写篇题解纪念一下首先考虑如果全是$-1$怎么处理。由于我们不关心每个pair中的max是多少,并且显然每个pai
Code submitted as solutions to contest exercises on AtCoder atcoderatcoder-solutionsatcoder-contests UpdatedJan 15, 2022 Python Hints & Solutions of Competitive Programming Problems of several Online Judges like Codeforces, AtCoder, UVA, LightOJ, SPOJ, InterviewBit, HackerEarth, CodeChef, HackerRank ...
从某种程度上来说,更改了部分思路,和 https://oj.leetcode.com/problems/candy/有点像。 代码语言:javascript 代码运行次数:0 运行 AI代码解释 import java.util.Scanner;public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int count = sc.nextInt()...