Note that the coefficient of the each term in the right hand side is no greater than 106106, so one may find the convolution modulo 998244353998244353 (which we can directly obtain with the convolution function in ACL). ABC394 这场过了 ABCDFG。获得了 ARC 资格,但是不知道获没获得 ARC 实力...
convolution(T, P3) MAX = n + m + m - 2 if len(res1) < MAX: res1.extend([0 for _ in range(MAX - len(res1))]) if len(res2) < MAX: res2.extend([0 for _ in range(MAX - len(res2))]) if len(res3) < MAX: res3.extend([0 for _ in range(MAX - len(res3))]...
vector <T>convolution<mod>(vector <T> a, vector <T> b) vector <ll>convolution_ll(vector <ll> a, vector <ll> b) 其中T是int, uint, ll, ull其中之一或者 ACL 的static_modint类型。 前者基于 NTT 实现,所以你需要保证modmod是一个满足存在cc使得2c|mod−12c|mod−1且|a|+|b|−1≤...
#include<atcoder/convolution>#include<cstdio>usingnamespacestd;usingnamespaceatcoder;intmain(){intn,m;scanf("%d %d",&n,&m);vector<longlong>a(n),b(m);for(inti=0;i<n;i++){scanf("%lld",&(a[i]));}for(inti=0;i<m;i++){scanf("%lld",&(b[i]));}vector<longlong>c=convol...
#include <bits/stdc++.h> #include <atcoder/modint> #include <atcoder/convolution> #define FOR(i, a, b) for (int i = (a); i <= (b); ++i) using namespace std; using mint = atcoder::modint998244353; using atcoder::convolution; const int maxn = 2e5 + 5; vector<vector<min...
max-plus convolution and some using segtree + divide and conquer segtree + divide and conquer . I am unable to understand both of them pls help :( →Reply Azm1t 12 months ago,#^| ←Rev.3→ 0 Sort the items in order of increasing ...
.gitmodules #95: fix convolution Jan 18, 2021 LICENSE make LICENSE as CC0 Mar 15, 2023 README.md Merge pull request #130 from tockrock/patch-1 Mar 17, 2023 expander.py expander.py: trace line numbers back to the original source file Dec 14, 2023 ...
AtCoder (ABC 382)比赛于本周六晚20:00进行,同学们参与比赛后可在本周日(11月30日)晚 19:00进入继续到直播间观看题目解析。 欢迎加入ABC交流QQ群咨询、沟通、交流(群密码:AtCoder) ABC381比赛真题讲解 题目列表: 题目地址:https://atcoder.jp/contests/abc380/tasks ...
解压zip 文件后将atcoder,放置GCC的对于库文件夹下。 使用g ++,可以通过g++ main.cpp -std=c++14 -I .将atcoder文件夹放在与相同的位置进行编译main.cpp。 您应该使用-std=c++14或进行编译-std=c++17。 有关更多详细信息,请参见附录。 笔记 如果输入与约束不匹配,则行为未定义。
F– Convolution FFT 卷积 G– SCC 强连通分量 H– Two SAT 2SAT I– Number of Substrings 后缀数组 里面的实现用的是sa-is线性构造算法。 –https://atcoder.jp/contests/abc141/submissions/23884310 –https://atcoder.jp/contests/arc097/tasks/arc097_a ...