https://blog.csdn.net/gui_tou_zai/article/details/127079615 AtCoder Beginner Contest 269「A」「B」「C 二进制枚举」「D 暴力dfs」「E 二分答案」「F 等差数列+推式子」 https://suryxin.blog.csdn.net/article/details/126974824 AtCoder Beginner Contest 269(E-EX) https://www.bilibili.com/opus/7...
A - Anyway Takahashi 这里我还是关了ll的 C开了忘了关 害的F多了一发罚时 #include<bits/stdc++.h> usingnamespacestd; constintN =3e5+10; constintM =998244353; constintmod =998244353; //#define int long long #defineendl'\n' #defineall(x) (x).begin(),(x).end() #defineYES cout<...
给定参数a, b, c, d,输出(a + b) * (c - d)加一个名字即可。 代码: signedmain(){int a,b,c,d;cin>>a>>b>>c>>d;cout<<(a+b)*(c-d)<<endl;puts("Takahashi");} B - Rectangle Detection 模拟 题意: 输入一个10 * 10的矩阵,求#的矩阵的左上角和右下角。 分析: 根据题意模拟即...
// Contest: AtCoder - UNICORN Programming Contest 2022(AtCoder Beginner Contest 269) // URL: https://atcoder.jp/contests/abc269/tasks/abc269_f // Memory Limit: 1024 MB // Time Limit: 3000 ms // // Powered by CP Editor (https://cpeditor.org) ...
AtCoder Beginner Contest 174 题解 AtCoder Beginner Contest 174 题解C Repsept 知识点:取模对加法和乘法封闭,所以暴力到2×1062\times 10^62×106,一边取模一边特判即可。D - Alter Altar 最终肯定是RRR全在左边,简单证明:假设最终RRR左边的某个位置存在WWW,则该位置右边只能是WWW,然后就是子问题了...
AtCoder Beginner Contest 216 个人题解 每篇一图 A题 Signed Difficulty 题目大意: 给出一个小数,根据小数部分改写 \(+,-\) 思路解析: 直接判断即可 AC代码: #include<bits/stdc++.h> using namespace std; int main(){ int x,y; scanf("%d.%d",&x,&y);...
We will hold AtCoder Beginner Contest 199(Sponsored by Panasonic). Start Time: Duration: 100 minutes Number of Tasks: 6 Writer:evima, kyopro_friends,QCFium,satashun,YoshikaMiyafuji Rated range: ~ 1999 If any of the vertices of a component have degree 3 or higher so our total answer is ...
We will hold AtCoder Beginner Contest 167. Contest URL: https://atcoder.jp/contests/abc167 Start Time: http://www.timeanddate.com/worldclock/fixedtime.html?iso=20200510T2100&p1=248 Duration: 100 minutes Number of Tasks: 6 Writer: gazelle, kort0n, kyopro_friends, potetisensei, she...
给定参数a, b, c, d,输出(a + b) * (c - d)加一个名字即可。 代码: signed main() { int a, b, c, d; cin >> a >> b >> c >> d; cout << (a + b) * (c - d) << endl; puts("Takahashi"); } B - Rectangle Detection 模拟 题意: 输入一个10 * 10的矩阵,求#的矩...
AtCoder Beginner Contest 402(A-F详细题解) A 思路:我们直接输出字符串中的大写字母即可。 代码:#include<bits/stdc++.h> using namespace std; #define int long long #define N 500010 signed main(){ string s;cin>>… 秋日薄雾打开...