cout << (x < t || s <= x ?"Yes":"No") <<'\n'; } } B - Takahashi's Secret 思路分析: 这题我想的是dfs跑一遍,如果之前跑过这个点那么就退出即可,dfs一次就加一次。 代码如下: #include<bits/stdc++.h>usingnamespacestd;constintmaxn =1e5+10; vector<int> e[maxn];boolvis[maxn];...
· AtCoder Beginner Contest 228D - Linear Probing · AtCoder Beginner Contest 238 · AtCoder Beginner Contest 272 - G - Yet Another mod M · AtCoder Beginner Contest 269 (A-F)题解 · AtCoder Beginner Contest 313 A-E Code 阅读排行: · dotnet 9 通过 AppHostRelativeDotNet 指定...
C - Final Day 题意:现有n人参加考试,每人已经有分数a_i,还需要考一场300分满分的测试。 对于每个人,在现有的分数的前提下,判断其是否有可能进入前K名? 分析:贪心地认为其他人在测试中获得0分,自己获得300分,所以考察a_i+300在a数组中是否能排前k名即可。 这里为了让 upper_bound不越界,设置了第n+1个...
AtCoder Beginner Contest 401 A-G 简易题解,如果题解中有什么问题可以找我反馈,谢谢!(感觉这次格式搞得有点怪,回头再调下) A.Status Code直接判断即可。 int main(){ int n; cin >> n; if(n >= 200 &… 枫落发表于Atcod... AtCoder Beginner Contest 400 A-F LHao Atcoder Begi...
AtCoder Beginner Contest 283 https://www.cnblogs.com/cilinmengye/p/17008799.html https://blog.csdn.net/m0_74946315/article/details/128540553 https://www.cnblogs.com/Lanly/p/17003594.html AtCoder Beginner Contest 283 A - Power https://www.bilibili.com/video/BV1G14y1P7oc/ ...
AtCoder Beginner Contest 287-E题(字典树/Trie https://zhuanlan.zhihu.com/p/603720615 AtCoder Beginner Contest 287 D 和 E https://zhuanlan.zhihu.com/p/602258994 AtCoder Beginner Contest 287 DEF EX https://zhuanlan.zhihu.com/p/613355266 ...
AtCoder Beginner Contest 169(题解)E - Count Median结论题给定nnn个xi∈[ai,bi]x_i\in[a_i,b_i]xi∈[ai,bi],求中位数的个数。定义:k=⌊n2⌋k=\lfloor\dfrac{n}{2}\rfloork=⌊2n⌋,对a,ba,ba,b进行排序后,为ak+1a_{k+1}ak+1为aia_iai的中位数,bk+1...
AtCoder Beginner Contest 193 部分题解 E - Oversleeping 求是否存在\(t\)满足\(t=t_1(mod (2X+2Y)) and t=t_2(mod (P+Q))\) 注意到\(Q\)和\(Y\)非常小,直接枚举套个\(exCRT\)就行了(虽然赛场上没看出来,\(exCRT\)也忘了记得快速乘...
Did you enjoy the AtCoder Beginner Contest 128? A Japanese editorial is already out, but unfortunately there is no English editorial, so I translated it into English experimentally. Note that this is an unofficial one; AtCoder has no responsibility for this editorial. Also, I didn't do ...
We will hold KEYENCE Programming Contest 2021 (AtCoder Beginner Contest 227). Contest URL: https://atcoder.jp/contests/abc227 Start Time: http://www.timeanddate.com/worldclock/fixedtime.html?iso=20211113T2100&p1=248 Duration: 100 minutes Number of Tasks: 8 Writer: blackyuki, kyopro_...