AtCoder Beginner Contest 075 C bridge 桥就是指图中这样的边,删除它以后整个图不连通。本题就是求桥个数的裸题。 dfn[u]指在dfs中搜索到u节点的次序值,low[u]指dfs栈中u能追溯到的最早栈中节点从次序号。这里写的很好。 #include<bits/stdc++.h>usingnamespacestd;constintmaxn=50
Dolphin loves programming contests. Today, he will take part in a contest in AtCoder. In this country, 24-hour clock is used. For example,9:00p.m. is referred to as "21o'clock". The current time isAo'clock, and a contest will begin in exactlyBhours. When will the contest begin?
Dolphin loves programming contests. Today, he will take part in a contest in AtCoder. In this country, 24-hour clock is used. For example,9:00p.m. is referred to as "21o'clock". The current time isAo'clock, and a contest will begin in exactlyBhours. When will the contest begin?
A.First ABC 2模拟即可。 inlinevoidqfl_zzz(){ll n=read();string s=sread();for(ll i=1;i<=n-2;++i)if(s[i]=='A'&&s[i+1]=='B'&&s[i+2]=='C'){writen(i);return;}writen(-1);} B.Prefix and Suffix模拟即可。 inlinevoidqfl_zzz(){ll n=read(),m=read();string s=sr...
·AtCoder Beginner Contest (ABC) 这是最频繁且最简单的入门赛,通常情况下每月至少举行2次。2019年4月27日(含)之前,每场比赛共4题,时长100分钟,满分1000分且Rating超过1199的选手不计Rating值。自2019年5月19日起改版升级为6道题目,时长不变,满分2100分且Rating值超过1999的选手不计Rating值。改版之后比赛质量...
头一次写题解。 A - A Healthy Breakfast r在m前面输出Yes,反之输出No。 统计两个位置比一下就行。 voidsolve(){strings;cin>>s;inta=0,b=0;for(inti=0;i<3;i++)if(s[i]=='R')a=i;elseif(s[i]=='M')b=i;if(a<b)yes;elseno;} ...
AtCoder Beginner Contest 173的A题是什么类型的问题? 在AtCoder Beginner Contest 173中,B题的解决方案有哪些关键点? AtCoder Beginner Contest 173的C题是否涉及到数据结构的应用? A 签到: 代码语言:javascript 代码运行次数:0 运行 AI代码解释#include<iostream> using namespace std; int main(){ int n; ...
AtCoder Beginner Contest 070 will be held. Time:August 12th (Saturday),21:00 JST Duration: 100 minutes Number of Tasks: 4 writer:Hec Rating: 0-1199 The point values are: 100 — 200 — 300 — 400 We are looking forward to your participation!
Atcoder Beginner contest 256题解(A-G) A.2^N直接输出好了 #include <bits/stdc++.h> using namespace std; using ll = long long; #define fi first #define se second #define pb push_back #define sz(x) ((int)x.size()… syyy Win10+MinGw编译可被Python调用的dll库 最近在项目中...
This is the approach I implemented during the contest. Of course, I'm (mostly--I actually did do this during the contest) joking, and I'll now describe the solution I assume was intended. The basic idea is that there are two cases to deal with. First, two points form a diameter of...