ABC264E 反向处理询问+并查集加粗样式 ABC261F 逆序对+树状数组+思维 ABC260D map,set妙用 ABC250D hash 二分 ABC273D map的使用+二分 ABC270E 忘了加粗样式 ARC144B 忘了加粗样式 ARC138A 前缀最大值数组上的二分 构造 ARC149C 考虑一般情况用奇偶数+用特殊数字3的倍数处理好特殊位置 ...
// Problem: E - Blackout 2 // Contest: AtCoder - freee Programming Contest 2022(AtCoder Beginner Contest 264) // URL: https://atcoder.jp/contests/abc264/tasks/abc264_e // Memory Limit: 1024 MB // Time Limit: 3000 ms // // Powered by CP Editor (https://cpeditor.org) #include...
abc021 D - 多重ループ 二項係数 agc025 B - RGB Coloring 二項係数, 素因数分解 arc077 D - 11 二項係数 arc116 C - Multiple Sequences 二項係数, 素因数分解 practice2 B - Fenwick Tree Binary Indexed Tree abc038 D - プレゼント Binary Indexed Tree abc036 C - 座圧 座標圧...
Search or jump to... Search code, repositories, users, issues, pull requests... Provide feedback We read every piece of feedback, and take your input very seriously. Include my email address so I can be contacted Cancel Submit feedback Saved searches Use saved searches to filter your...
https://atcoder.jp/contests/abc264 A - "atcoder".substr() 输出atcoder第L位到第R位上的字符 #include <bits/stdc++.h> using namespace std; int main () { string s = "atcoder"; int x, y; cin >> x >> y; x --, y --; for (int i = x; i <= y; i ++) cout << s...
摘要:ABC略。 D. Make It Round 问题可以看成凑出尽可能多的1010作为因子。 注意到1010的因子只有1,2,5,101,2,5,10。 首先,nn自己已经凑出来的1010没必要拆开,并不会更优。 然后就是看nn有多少个多余的22或者55,然后kk先尽阅读全文 » AtCoder Beginner Contest 277 ...
ABC226_A.py ABC226_B.py ABC226_C.py ABC226_D.py ABC226_E.py ABC226_F.py ABC226_G.py 227 228 229 230 231 232 233 234 235 236 237 238 239 240 241 242 243 244 245 246 247 248 249 250 251 252 253 254 255 256 257 258 259 260 261 262 263 264 265 266 267 268 269 270...
Available add-ons Advanced Security Enterprise-grade security features GitHub Copilot Enterprise-grade AI features Premium Support Enterprise-grade 24/7 support Pricing Search or jump to... Search code, repositories, users, issues, pull requests... Provide feedback We read every piece of ...
// Problem: F - Tournament // Contest: AtCoder - LINE Verda Programming Contest(AtCoder Beginner Contest 263) // URL: https://atcoder.jp/contests/abc263/tasks/abc263_f // Memory Limit: 1024 MB // Time Limit: 2000 ms // // Powered by CP Editor (https://cpeditor.org) #include ...
D - Christmas Time limit時間制限 : 2sec /Memory limitメモリ制限 : 1024MB Score :400points Problem Statement In some other world, today is Christmas. Mr. Takaha decides to make a multi-dimensional burger in his party. Alevel-Lburger(Lis an integer greater than or equal to0) is the foll...