ABC265E map存状态+步骤型遍历(注意DP顺序)+复杂度证明 ABC262D 关于数字的DP,将一类数字分成一个状态加粗样式 ABC261D 没啥好说的 看题目写DP ABC253E 关于数字的DP ABC251E 状态机DP ABC197E 在一维轴上行走的DP 数据结构 ABC264E 反向处理询问+并查集加粗样式 ABC261F 逆序对+树状数组+思维 ABC260D...
https://atcoder.jp/contests/abc264 输出atcoder第L位到第R位上的字符 #include<bits/stdc++.h>usingnamespacestd;intmain(){ string s ="atcoder";intx, y; cin >> x >> y; x --, y --;for(inti = x; i <= y; i ++) cout << s[i]; } ...
【算法竞赛】AtCoder - ABC - VP 代码实现都在账号 Livinfly 中,可在AtCoder所有提交中查看。 abc042 b,sort。 c,从小到大枚举 i >= n,判断有没有不喜欢的数字。 1K20 扫码 添加站长 进交流群 领取专属10元无门槛券 手把手带您无忧上云 相关资讯 ...
AtCoder Beginner Contest 264 传送门 https://atcoder.jp/contests/abc264 Table of Contents Problem C. Matrix Reducing 数据范围很小,随便做。 + expand source Problem D. “redocta”.swap(i,i+1) 暴力求下逆序对。 Problem E. Blackout 2
// Problem: E - Blackout 2 // Contest: AtCoder - freee Programming Contest 2022(AtCoder Beginner Contest 264) // URL: https://atcoder.jp/contests/abc264/tasks/abc264_e // Memory Limit: 1024 MB // Time Limit: 3000 ms // // Powered by CP Editor (https://cpeditor.org) #include...
// Problem: F - Tournament // Contest: AtCoder - LINE Verda Programming Contest(AtCoder Beginner Contest 263) // URL: https://atcoder.jp/contests/abc263/tasks/abc263_f // Memory Limit: 1024 MB // Time Limit: 2000 ms // // Powered by CP Editor (https://cpeditor.org) #include ...
abc021 D - 多重ループ 二項係数 agc025 B - RGB Coloring 二項係数, 素因数分解 arc077 D - 11 二項係数 arc116 C - Multiple Sequences 二項係数, 素因数分解 practice2 B - Fenwick Tree Binary Indexed Tree abc038 D - プレゼント Binary Indexed Tree abc036 C - 座圧 座標圧...
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1449 ABC081B - Shift only C++ 17 (gcc 12.2) AtCoder *200 Aug/19/2024 22:04 1448 A - Entrance Examination C++ 17 (gcc 12.2) AtCoder *100 Aug/19/2024 22:03 1447 D - Pedometer C++ 17 (gcc 12.2) AtCoder *400 Aug/17/2024 19:04 1446 C - Enumerate Sequences C++ 17 (gcc 12.2...