然而,这通常不是consistent-return规则的直接含义。expected no return value更可能是在描述一个具体的函数预期行为,即该函数不应该显式地返回任何值。 说明consistent-return ESLint规则的含义: consistent-return是ESLint中的一个规则,用于确保函数在所有执行路径上要么都返回值,要么都不返回值。如果函数在某些路径上返...
包括地震、海啸、各类事件、各类新闻的drp错误集锦—“Cannot return from outside a function or method...
Example 1: Arrow Function With No Argument If a function doesn't take any argument, then you should use empty parentheses. For example, constsayHello =()=>"Hello, World!"; // call the arrow function and print its return valueconsole.log(sayHello());// Output: Hello, World! Run Code ...
self.age = 0; setInterval(function growUp() { // The callback refers to the `self` variable of which // the value is the expected object. self.age++; }, 1000); } 或者是,透過綁定函數的作法來綁定 this 變數到 growUp 函數。 不過現在箭頭函數會自動將 this 變數綁定到其定義時所在的物件,...
Array.prototype.map() expects a value to be returned at the end of arrow function Question: While utilizing array.map() arrow function in my code, I encountered an error that states "Array.prototype.map() expectsa value must be returned by the end ofarrow function array-callback-ret...
"Expected to return a value at the end of async arrow function consistent-return." I use it on an onChange since I would like the URL put in the input to be used. const handleChange = async (event) => { try { const article = await extract(event.target.value) ...
// ✅ No errors with `except-parens` value const funcA(a, b) { return a == b + 1; } function funcB(a, b) { return a === b + 1; } function funcC(a, b) { return (a = b + 2); } const funcD = (a, b) => (a = b) ...
function. The arrow function has one parameter, num . As there is only one parameter, we’ve omitted parenthesis around the parameter. Since we want to return the value of num * 2 we’ve also omitted the brackets around the expression to return. Let’s invoke the function and see it ...
function*foo(){ yield1; yield2; }for(let o of foo()) { console.log(o);//expected output: 1break;//closes iterator, triggers return} 注意: 如果不在块内重新分配变量,则可以使用const而不是let。 demo: let iterable = [10, 20, 30];for(const value of iterable) { ...
function Prefixer(prefix) { this.prefix = prefix; } Prefixer.prototype.prefixArray = function (arr) { var that = this; // (A) return arr.map(function (x) { return that.prefix + x; }); }; Now Prefixer works as expected:> var pre = new Prefixer('Hi '); > pre.prefixArray(['...