sort方法的使用非常的简单明了,下面的例子中,先定义一个比较Dog大小的Comparator,然后将其实例对象作为参数传给sort方法,通过此示例,你应该能够快速掌握Arrays.sort()的使用方法。 importjava.util.Arrays;importjava.util.Comparator;classDog{intsize;publicDog(ints){ size = s; } }classDogSizeComparatorimplements...
publicstaticvoidsort(Object[] a) {if(LegacyMergeSort.userRequested) legacyMergeSort(a);elseComparableTimSort.sort(a,0, a.length,null, 0, 0); }publicstatic<T>voidsort(T[] a, Comparator<?superT>c) {if(c ==null) { sort(a); }else{if(LegacyMergeSort.userRequested) legacyMergeSort(a,...
Arrays.sort(a); Sorts in "natural" order. If object type, elements must be comparable. Arrays.sort(a, comp); Sorts objects (not primitives) using comparator. Arrays.sort(a, from, to); Sorts subrange, including a[from] excluding a[to]. Arrays.sort(a, from, to, comp); Sorts objects...
import java.util.Arrays; import java.util.Comparator; /** * Arrays.sort()排序 */ public class SortTest { public static void main(String []args) { int[] ints=new int[]{2,324,4,57,1}; System.out.println("增序排序后顺序"); Arrays.sort(ints); for (int i=0;i { System.out.p...
后面则对剩余部分lo+minRun到hi进行上面的操作,直到nRemaining变为0。 如果是传入实现Comparator接口的匿名内部类大致思路与上面相同,只是compareTo变成重写的compare方法,二者基本相同。以上是自己对Array.sort进行自定义数据排序粗浅的理解,如有错误,请多包涵指正。
static<T>voidsort(T[] a,intlo,inthi, Comparator<?superT> c, T[] work,intworkBase,intworkLen){assertc !=null&& a !=null&& lo >=0&& lo <= hi && hi <= a.length;intnRemaining=hi - lo;if(nRemaining <2)return;// Arrays of size 0 and 1 are always sorted// If array is sm...
Java的Arrays类中有一个sort()方法,该方法是Arrays类的静态方法,在需要对数组进行排序时,非常的好用。 但是sort()的参数有好几种,基本上是大同小异,下面是以int型数组为例的Arrays.sort()的典型用法 importjava.util.Arrays;importjava.util.Comparator;/** ...
parallelSort(Object[] a[, int fromIndex, int toIndex]) 或者 parallelSort(T[] a[, int fromIndex, int toIndex,] Comparator<? super T> c) 代码示例: public void sortTest() { String[] str = { "abc", "add", "java", "hello", "javascript" ...
staticvoid sort(T[] a, int lo, int hi, Comparator super T> c, T[] work, int workBase, int workLen) { assert c != null && a != null && lo >= 0 && lo <= hi && hi <= a.length; int nRemaining = hi - lo; if (nRemaining < 2) ...
public static void sort(Object[] a) {if (LegacyMergeSort.userRequested) legacyMergeSort(a); elseComparableTimSort.sort(a, 0, a.length, null, 0, 0); } public static <T> void sort(T[] a, Comparator<? super T> c) {if (c == null) { ...