We remove the last element at each iteration step and fill it to thei-thposition usinglist.add(i, list.remove(j)). Whenireachesj-1, the loop ends, and we’ve reversed the list: Iteration step 0: i = j = null, list = (1, 2, 3,...7) Iteration step 1: i = 0; j = 6 ...
A 3. Add and Remove Elements during Iteration ListIteratorsupports adding and removing elements in the list while we are iterating over it. listIterator.add(Element e)– The element is inserted immediately before the element that would be returned bynext()or after the element that would be re...
2.3. Iteration The iteration is theO(n)operation for bothLinkedListandArrayListwhere the list contains‘n’items. 2.4. Get an Element ArrayList providesget(int index),which directly finds the element at a given index location. It is of orderO(1). ...
al.set(5, "F"); // It will not throw ConcurrentModificationException during Iteration. String str = itr.next(); System.out.println(str); } System.out.println(al); } } Output: [A, B, null, D, E, H] A B null D E H [A, B, null, D, E, F] 正如您在上面的程序中观察到...
{consumer.accept((E)elementData[i++]);}// update once at end of iteration to reduce heap ...
{consumer.accept((E)elementData[i++]);}// update once at end of iteration to reduce heap ...
{String name;int size;Tester(String name,int size){this.name=name;this.size=size;}abstractvoidtest(List a);}privatestaticTester[]tests={newTester("get",300)//一个测试数组,存储get(随机取)、iteration(顺序遍历)、insert(中间插入)、remove(随机删除){voidtest(List a){for(int i=0;i<REPS;i...
* (In other words, returns {@codetrue} if {@link#next} would * return an element rather than throwing an exception.) * *@return{@codetrue} if the iteration has more elements*/booleanhasNext();/*** Returns the next element in the iteration. ...
java集合【8】-- ArrayList接口源码解析 1. ArrayList ArrayList是最最常用的集合类了,真的没有之一。下面的分析是基于1.8.0_261源码进行分析的。 1.1 ArrayList特点介绍 动态数组,使用的时候,只需要操作即可,内部已经实现扩容机制。 线程不安全 有顺序,会按照添加进去的顺序排好...
// update once at end of iteration to reduce heap write traffic !!! cursor = i; lastRet = i - 1; checkForComodification(); } final void checkForComodification() { if (modCount != expectedModCount) throw new ConcurrentModificationException(); ...