Convert an array list to a linked list. Example Example 1: Input: [1,2,3,4], Output:1->2->3->4->null 定义两空指针,一个用来返回整个链表,一个用来创建新节点。 新创建的节点作为当前p的next节点,再把p重新指向新创建的节点。 publicListNode toLinkedList(List<Integer>nums) {if(nums.size()...
1/**2* Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.3* list can be accessed in order only4*@paramhead5*@return6*/7publicTreeNode sortedListToBST(ListNode head){8if(head ==null)9returnnull;10intlen = 0;11ListNode temp ...
leetcode(121-140)简单题python 532. K-diff Pairs in an Array(121) Given an array of integers and an integer k, you need to find the number of unique k-diff pairs in the array. Here a k-diff pair is defined as an integer pair (i, j JSON简介-01 很容易的进行阅读和编写 2.JSON...
[LeetCode]23.Merge k Sorted Lists 【题目】 Mergeksorted linked lists and return it as one sorted list. Analyze and describe its complexity. 【分析】 无 【代码】 这种方法超时。。。 【分析二】 采用最小优先级队列。 第一步:把非空的链表装进最小优先级队列中。 第二步:遍历最小优先级队列,...
leetcodearraysortdata-structuresleetcode-solutionsinterview-questionscoding-practicesalogrithms UpdatedDec 29, 2024 teivah/algodeck Sponsor Star5.7k Code Issues Pull requests An Open-Source Collection of Flash Cards to Help You Preparing Your Algorithms & Data Structures and System Design Interviews 💯...
题目链接:https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/ 题目: Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 思路: 新建一个结点保存mid值,该结点的左右子树也递归生成,这是个常用的模板 ...
package leetcode func search33(nums []int, target int) int { if len(nums) == 0 { return -1 } low, high := 0, len(nums)-1 for low <= high { mid := low + (high-low)>>1 if nums[mid] == target { return mid } else if nums[mid] > nums[low] { // 在数值大的一部分...
83 -- 5:41 App Leetcode-0111. Minimum Depth of Binary Tree 76 -- 1:11 App Leetcode-0104. Maximum Depth of Binary Tree 8 -- 5:41 App Leetcode-0110. Balanced Binary Tree 23 -- 6:11 App Leetcode-0114. Flatten Binary Tree to Linked List 89 -- 1:36 App Leetcode-0067....
def sortedArrayToBST(self, nums: List[int]) -> TreeNode: if not nums: return if len(nums) == 1: node = TreeNode(nums[0]) return node if len(nums) == 2: node1 = TreeNode(nums[0]) node2 = TreeNode(nums[1]) node2.left = node1 ...
[leetcode]convert-sorted-array-to-binary-search-tree RioDream 2014-04-21 阅读2 分钟RT 思路 a height balanced BST BST的中序遍历是一个sorted-array,再构造回去成一个BST,先将中间的元素作为根节点,这个节点的左右分别是左子树和右子树。如此递归地进行即可。 Solution 1 /** * Definition for binary ...