Casting - Convert from uint8_t * to char * in C, Convert from uint8_t * to char * in C. I am programming in C using Atmel Studio (for those unfamiliar with this it is used to program to micro controllers such as arduino. You can not simply print, you have to send the data S...
How to convert an int to hex (uint8) and split it into 2 bytes, Double a needs to be converted to hex (uint8), double b needs to be converted to hex, and then split into 2 uint8 variables. Then i need to put them in an array of uint8's like this: const uint8 rawSys...
Consider an integer array, of sizen, that has elements either from the range 0 ton-1or -1. The task at hand is to arrange the array in such a way that thearray[i] = i. If the corresponding element is not present, then fill the position with -1. ...
// java program for implementation of stack using array class Stack { static final int capacity = 5; int top; int a[] = new int[capacity]; // Maximum size of Stack boolean isEmpty() { return (top < 0); } Stack() { top = -1; } boolean push(int x) { if (top >= (capacit...
Reversal Algorithm of Array Rotation Block Swap Algorithm for Array Rotation Program to Cyclically Rotate an Array by One Search an element in a sorted and rotated array Given a sorted and rotated array, find if there is a pair with a given sum Find maximum value of ...
The following program demonstrates in-place reversal of array. import java.util.Arrays; public class Main { /*swap the first elemnt of array with the last element; second element with second last and so on*/ static void reverseArray(intintArray[], int size) ...
Since in-place reversal is an efficient algorithm and doesn't require extra memory, you can use it to sort and reverse large arrays as well. You can also see a comprehensive course on data structure and algorithms likeData Structures and Algorithms: Deep Dive Using Javato learn more about ef...
Solution 1: Using Temporary Array This is a simple approach that involves using a temporary array as we need the original to be unchanged since we perform multiple rotations. It involves following steps: Create a temporary array of size2n ...
Split the into two groups,G1 = array[0..d-1]andG2 = array[d..n-1] If the length ofG1is lesser thanG2, then splitG2into two groups,G2LandG2R, in such a way that the size ofG1is the same asG2R. SwapG1andG2R. The order of array will look like,G2R,G2L,G1. ...
C++ Implementation: #include <iostream>usingnamespacestd;// Function to print the arrayvoidprintArray(intarray[],intlength) {for(inti=0; i<length; i++) { cout<<array[i]<<" "; } }// Fucntion to replace the array elementsvoidreplaceArray(intarray[],intlength) {inttem...