https://leetcode.com/problems/remove-duplicates-from-sorted-array/ 题意分析: 给定一个排好序的数组,去除重复的数,返回新数组的长度,不能申请额外的空间,超过新数组长度部分是什么数都无所谓。 题目思路: 这是一个很简单的题目,由于给定的数组已经排序,那么用i,j两个下标,i记录新数组的下标,j是原来数组下...
Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example, Given input array nums = [1,1,2], Your function should re...
算法题目 Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example, Given input array A = [1,1,2], Your function sh...
Given a sorted arraynums, remove the duplicates in-place such that each element appear onlyonceand return the new length. Do not allocate extra space for another array, you must do this bymodifying the input arrayin-place Example 1: Givennums=[1,1,2], Your ...
Follow up for "Remove Duplicates": What if duplicates are allowed at most twice? For example, Given sorted array nums = [1,1,1,2,2,3], Your function should return length = 5, with the first five elements of nums being 1, 1, 2, 2 and 3. It doesn't matter what you leave beyon...
C++ Java Python #include<bits/stdc++.h> using namespace std; void removeDuplicates(vector<int> a,int n){ vector<int> res; sort(a.begin(),a.end()); for(int i=0;i<n-1;i++){ if(a[i]!=a[i+1]) res.push_back(a[i]); } res.push_back(a[n-1]); for(auto x:res) co...
Python Array用Dicts删除“重复项” 您可以在一行中完成这一点: def remove_cookie_duplicates(cookies): return list({i["name"]: i for i in cookies}.values()) Breakdown {i["name"]: i for i in cookies} 这部分是一个dict理解词典,名称作为键,cookie本身作为值。字典的一个side-effect就是每个键...
Communication between Python and C# Communication between Threads Compare 2 arrays using linq compare a string to all possible dictionary keys compare two arrays to find out if they contain any element in common. Compare two bitmaps Compare two char arrays Compare two int arrays Compare two List(...
Python Code: class Solution: def removeDuplicates(self, nums: List[int]) -> int: if nums: slow = 0 for fast in range(1, len(nums)): if nums[fast] != nums[slow]: slow += 1 nums[slow] = nums[fast] return slow + 1 else: return 0 C++ Code: class Solution { public: int ...
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