json 需要操作太多 明显劣势于 (array)
针对您提出的json_decode() expects parameter 1 to be string, array given错误,我将按照给出的提示来逐步解答: 1. 确认错误信息的来源和上下文 这个错误信息表明在调用json_decode()函数时,其第一个参数被错误地传递了一个数组,而不是一个字符串。这通常发生在处理来自表单提交(如$_POST或$_GET)的数据时,...
json_decode($data)输出的是对象,而json_decode("$arr",true)是把它强制生成PHP关联数组. 2.json_encode() string json_encode ( mixed $value [, int $options = 0 ] ) 该函数只能接受 UTF-8 编码的数据 options 由以下常量组成的二进制掩码: JSON_HEX_QUOT, JSON_HEX_TAG, JSON_HEX_AMP, JSON_HE...
I am not sure how you storing the cookies are you encoding the data to json before you set it as a cookie, if you decoding the value you better have a encoded json object as a string, if you giving it an array literal then its gonna blow up $data = json_decode($value, true); ...
"components": { "temperature": { "platform": "sensor", "device_class": "temperature", "unit_of_measurement": "°C", "value_template": "{{(value|from_json)['temperature_1']}}", "unique_id": "28560BD60081-temperature" }, "humidity": { "platform": "sensor", "device_class": ...
1、使用 json_decode($d, true)。就是使json_decode 的第二个变量设置为 true。 2、json_decode(re个对象,不以用res['key'] 进行访问, 换成 参考手册:json_decode Return Values:Returns an object or if the optional assoc parameter is TRUE, an associative array is instead returned....
$json2array = json_decode($json,TRUE);加上True即可! <?php $json = "{\"code\":\"A00006\",\"data\": { \" uid\": { \"relation\":\"0\", \"gid\": \"11\", \"stat\" : \"\" } }}";$json2array = json_decode($json);//$json2array = json_decode($json,TRUE)...
(73): json_decode(Array, true) #1 /srv/www/wp-content/plugins/all-in-one-seo-pack-pro/app/Common/Traits/Helpers/Vue.php(229): AIOSEO\Plugin\Common\Help\Help->getDocs() #2 /srv/www/wp-content/plugins/all-in-one-seo-pack-pro/app/Common/Traits/Helpers/Vue.php(67): AIOSEO\Plugin...
<?php //PHP program to decode the Json string into //associative array. $json = '{"Id1":101,"Id2":102,"Id3":103,"Id4":104}'; $ids = json_decode($json); foreach ($ids as $key => $value) { print ("Key: " . $key . " Value: " . $value . "<br/>"); } ?> ...
PHP json_decode object时报错Cannot use object of type stdClass as array php再调用json_decode从字符串对象生成json对象时,如果使用[]操作符取数据,会得到上面的错误 解决方法(2种): 1、使用 json_decode($data, true)。就是使json_decode 的第二个变量设置为 true。 2、json_decode($res) 返回的是一...