0 1 0 1 2 1 3 4 代码语言:javascript 代码运行次数:0 运行 AI代码解释 当然了你也可以主动指定行和列索引(不赘述): >>> pd.DataFrame(np.array(s),index=['one', 'two'], columns=['year', 'state']) year state one 1 2 two 3 4 4:传入其他的数据(初始化方式基本类似); 参考资料:《利...
3、for...in 和 while循环区别 1)相同点:冒号和内部代码的缩进都是必不可少的; 2)不同点:【循环的工作量是否确定】,for循环就像空房间依次办理业务,直到把【所有工作做完】才下班。但while循环就像哨卡放行,【满足条件就一直工作】,直到不满足条件就关闭哨卡。 所以说,当【工作量确定】的时候,就可以让for循环...
In [2]: data1 = [1, 2, 3, 4, 5, 6] # 列表转化为数组 np.array(data1) Out[2]: array([1, 2, 3, 4, 5, 6]) In [3]: data2 = (1, 2, 3, 4, 5, 6) # 元组转化为数组 np.array(data2) Out[3]: array([1, 2, 3, 4, 5, 6]) 1. 2. 3. 4. 5. 6. 7. 8...
Dim ws As WorksheetDim lastRow As Long, lastCol As LongDim arr(), arr1()Set ws = Sheets("Sheet1")With ws lastRow = ws.UsedRange.Rows.Count lastCol = ws.UsedRange.Columns.Count arr = ws.Range(.Cells(1, 1), .Cells(lastRow, lastCol))End Witharr1 = arr 4、把数据库查...
functiontestRange2Array(){vararr=Range("A1:B5").Value2for(xinarr){for(yinarr[x]){Debug.Print("行"+x.toString()+" 列"+y.toString()+" value = "+arr[x][y])}}} 用过VBA的应该都知道,这个输出应该是(VBA里数组获取单元格的数据后下标是从1开始,JS中是从0开始): ...
Plot the S-parameters of this array in the 900 MHz to 1.1 GHz range. Get s = sparameters(c,f); figure rfplot(s,{[1,1];[2,2];[3,3];[4,4]}); Plot the radiation pattern of this array at 1 GHz. Get pattern(c,f(11)) Circular Array of Dipoles Copy Code Copy Command ...
>>> lst = list(i for i in range(num)) >>> sys.getsizeof(lst) 879840 >>> a = array.array('i', lst) # i表示数组中元素的类型,具体支持的类型见下面的表格 >>> a.itemsize # 每个元素占用的内存大小,这里为4byte 4 >>> sys.getsizeof(a) # 可以看到,总的大小为400064=4*num+64,...
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int[] myLengthsArray = new int[4] { 2, 3, 4, 5 }; Array my4DArray=Array.CreateInstance( typeof(string), myLengthsArray ); for ( int i = my4DArray.GetLowerBound(0); i <= my4DArray.GetUpperBound(0); i++ ) for ( int j = my4DArray.GetLowerBound(1); j <= my4DArray.GetUppe...
vector<int> v1(begin(arr), end(arr)); vector<int> v2(arr->begin(), arr->end()); // Initialize a vector one element at a time. // using a range for loop. Not as efficient as using begin/end. vector<int> v3; for(int i : arr) { v3.push_back(i); } } 下...