num = number # define a method for checking number is Armstrong or not def isArmstrong(self) : # copy num attribute to the temp variable temp = self.num res = 0 # run the loop untill temp is not equal to zero while(temp != 0) : rem = temp % 10 res += rem ** 3 # ...
In this program, we will read an integer number and check number is Armstrong or not, and print an appropriate message on the console screen. Program/Source Code: The source code tofind the given number is Armstrong or not using theforloopis given below. The given program is compiled and...
In the above program, an Armstrong number of n digits is checked. When the user enters a number, it is taken as a string. The length property returns the length of a string. The number entered by the user is stored in a temp variable. And a while loop is used to iterate until its...
Below is the procedure for armstrong number in C temp = num rem = 0 WHILE temp IS NOT 0 rem ← temp modulo 10 sum ← sum + power(rem, digits); divide temp by 10 END WHILE IF sum equivalent to num PRINT Armstrong Number ELSE PRINT not an Armstrong Number END IF end procedure C P...
Now we are calculating the number of digits that user input has. For that, we have assigned num value to var, and we have taken a while loop. The while loop will be running until (var !=0) and then divide var by ten so that we can count the total number of digits in that numbe...
Check 3 Digit Armstrong Number #Python program to check 3 Digits Armstrong Number #Taking input from user num = int(input("Enter a number: ")) # Declarign and intilizing sum variable arsum = 0 #Coping orignal value into a temp veriable t = num #While loop for iteration till t is ...
// while loop for manipulating the number while (number) { // remain contains the last element of the number remain = number % 10; // result contains the cube of remain added to it result = result + (remain * remain * remain); // number is divided by 10 at each iteration // ...