num = number # define a method for checking number is Armstrong or not def isArmstrong(self) : # copy num attribute to the temp variable temp = self.num res = 0 # run the loop untill temp is not equal to zero w
Here, we have set the lower limit 100 in variable lower and upper limit 2000 in variable upper using Python range(). We have used for loop to iterate from variable lower to upper. In iteration, the value of lower is increased by 1 and checked whether it is an Armstrong number or not...
In this program, we will read an integer number and check number is Armstrong or not, and print an appropriate message on the console screen. Program/Source Code: The source code tofind the given number is Armstrong or not using theforloopis given below. The given program is compiled and...
while(temp>0) { t = temp%10; sum+= (t*t*t); temp = temp/10; } if(sum==num) { printf("\nNumber %d is armstrong number", num); } } getch(); } OUTPUT: Explanation: In this program, we have to find all Armstrong numbers between 1 and 1000. For this, we firstly initializ...
Now we are calculating the number of digits that user input has. For that, we have assigned num value to var, and we have taken a while loop. The while loop will be running until (var !=0) and then divide var by ten so that we can count the total number of digits in that numbe...
function Armstrong() { var flag,number,remainder,addition = 0; number = Number(document.getElementById("N").value); flag = number; while(number > 0) { remainder = number%10; addition = addition + remainder*remainder*remainder; number = parseInt(number/10); } if(addition == flag) {...