#include <stdio.h> int main() { int arms = 153; int check, rem, sum = 0; check = arms; while(check != 0) { rem = check % 10; sum = sum + (rem * rem * rem); check = check / 10; } if(sum == arms) printf("%d is an armstrong number.", arms); else printf("%d...
[C]Armstrong Number //1234 = 1^4 + 2^4 + 3^4 + 4^4;//341 = 3^3 + 4^3 + 1^3//类似于水仙花数#include<stdio.h>#include<math.h>intdigitCount(intn) {//此函数用于获取整数的位数inti =0;do{ n= n /10; i++; }while( n >0);returni; }intisArmstrong(intn) {intdigitNum...
Step 6 → Save the output to Sum variable Step 7 → If Sum equals to Arms print Armstrong Number Step 8 → If Sum not equals to Arms print Not Armstrong Number STOP 伪代码 (Pseudocode) 我们可以按如下方式起草上述算法的伪代码 - procedure armstrong : number check = number rem = 0 WHILE ...
Then, a while loop is used to loop through originalNumber until it is equal to 0. On each iteration, the last digit of num is stored in remainder. Then, remainder is powered by 3 (number of digits) using Math.pow() function and added to result. Here, remainder is converted to Doub...
This Object method has no use in this program.Secondly, we have to create an object of this class using a class name with parenthesis then we have to call its method for our output.Below is the implementation of the program,Python program to check Armstrong number using object oriented ...
If numbers arm and n are not equal, Then n is not an Armstrong number. Check or Detect an Armstrong Number program in C Language [For 3-Digit Number]: Here is the Armstrong number program implementation in C language. We are using the while loop to iterate over the number ( temp). ...
Armstrong number in C or Narcissistic number is an n-digit number equal to the sum of digits raised to the nth power of digits
using System;using System.Collections.Generic;using System.Linq;using System.Text;namespace Program{class Program{static void Main(string[] args){int num, remainder, sum = 0;Console.Write("Enter a number : ");num = int.Parse(Console.ReadLine());...
We loop through each integer in this range and call isArmstrong() to check if it is an Armstrong number. isArmstrong Method: This method takes an integer as input and checks whether it is an Armstrong number. It counts the digits using String.valueOf(num).length(). ...
#include <iostream> using namespace std; // create a class class Armstrong { // private data member private: int number; // public function with an int type parameter public: int armstrong(int n) { // copying the value of the parameter // into data members number = n; // declarin...