Here, we are going to learnhow to find the given number is Armstrong or not using for loop in Golang (Go Language)? Submitted byNidhi, on March 06, 2021 [Last updated : March 03, 2023] Checking Armstrong Number in Golang Problem Solution: ...
Importing Scanner: We import java.util.Scanner for taking user input. Main Method We prompt the user for a lower and upper bound. We loop through each integer in this range and call isArmstrong() to check if it is an Armstrong number. isArmstrong Method: This method takes an integer as ...
Python program to check Armstrong number using object oriented approach# Define a class for Checking Armstrong number class Check : # Constructor def __init__(self,number) : self.num = number # define a method for checking number is Armstrong or not def isArmstrong(self) : # copy num ...
Then, a while loop is used to loop through originalNumber until it is equal to 0. On each iteration, the last digit of num is stored in remainder. Then, remainder is powered by 3 (number of digits) using Math.pow() function and added to result. Here, remainder is converted to Doub...
(sum = 0) and temp = num = 1. Then we apply modulus operator(%) and various other operations to calculate new sum = sum + (t*t*t);. When we exit from for loop, we check whether the sum and number num is equal. If they are equal, then it is Armstrong’s number, and the ...
For example, myList.length returns 10 Initializing Arrays Using a loop: for (int i = 0; i < myList.length; i++) myList[i] = i; Declaring, creating, initializing in one step: double[] myList = {1.9, 2.9, 3.4, 3.5}; This shorthand syntax must be in one statement. ...
Note: In the above program, the cube of a number could be calculated using anexponent operator**. For example,sum += remainder ** 3; Example 2: Check Armstrong Number of n Digits // program to check an Armstrong number of n digits// take an inputconstnumber = prompt("Enter a positiv...
// declaring int type variables for indexing // and storing result int index, remain, result = 0; // while loop for manipulating the number while (number) { // remain contains the last element of the number remain = number % 10; // result contains the cube of remain added to it ...