num = number # define a method for checking number is Armstrong or not def isArmstrong(self) : # copy num attribute to the temp variable temp = self.num res = 0 # run the loop untill temp is not equal to zero while(temp != 0) : rem = temp % 10 res += rem ** 3 # ...
Problem Solution: In this program, we will read an integer number and check number is Armstrong or not, and print an appropriate message on the console screen. Program/Source Code: The source code tofind the given number is Armstrong or not using theforloopis given below. The given program...
Below is the procedure for armstrong number in C temp = num rem = 0 WHILE temp IS NOT 0 rem ← temp modulo 10 sum ← sum + power(rem, digits); divide temp by 10 END WHILE IF sum equivalent to num PRINT Armstrong Number ELSE PRINT not an Armstrong Number END IF end procedure C P...
In the above program, an Armstrong number of n digits is checked. When the user enters a number, it is taken as a string. The length property returns the length of a string. The number entered by the user is stored in a temp variable. And a while loop is used to iterate until its...
Now we are calculating the number of digits that user input has. For that, we have assigned num value to var, and we have taken a while loop. The while loop will be running until (var !=0) and then divide var by ten so that we can count the total number of digits in that numbe...
Check 3 Digit Armstrong Number #Python program to check 3 Digits Armstrong Number #Taking input from user num = int(input("Enter a number: ")) # Declarign and intilizing sum variable arsum = 0 #Coping orignal value into a temp veriable t = num #While loop for iteration till t is ...
// while loop for manipulating the number while (number) { // remain contains the last element of the number remain = number % 10; // result contains the cube of remain added to it result = result + (remain * remain * remain); // number is divided by 10 at each iteration // ...