# Python program to check if the number provided by the user is an Armstrong number or not # take input from the user num = int(input("Enter a number: ")) # initialize sum sum = 0 # find the sum of the cube of each digit temp = num while temp > 0: digit = temp % 10 sum...
n1 = number % 10 #取个位数 n2 = int(number/10 % 10) #取十位数 result = n1**2 + n2**2 if number == result: print(number) elif number < 1000: n1 = number % 10 n2 = int(number/10 % 10) n3 = int(number/100 % 10) #取千位数 result = n1**3 + n2**3 + n3**3 if...
In this Python tutorial, you will learn how to find Armstrong numbers using recursion in Python. Generally, the Armstrong number is a way to practice looping, conditions, etc., to gain programming skills and improve logical thinking. Although the Armstrong number is not actually used in real-ti...
It's an Armstrong Number. Cubing numbers:3*3*3 + 7*7*7 + 1= 371 (Armstrong Number) Conclusion We will go through lots of tricky logic and a simple one with Visual Studio in Python. We see it's very easy to implement it. Read more articles onPython: Diving Into Python: Chapter 1...
实例(Python 3.0+) # Filename : test.py # author by : www.runoob.com # Python 检测用户输入的数字是否为阿姆斯特朗数 # 获取用户输入的数字 num = int(input("请输入一个数字: ")) # 初始化变量 sum sum = 0 # 指数 n = len(str(num)) # 检测 temp = num while temp > 0: digit = ...
#Python program to check 3 Digits Armstrong Number#Taking input from usernum =int(input("Enter a number: "))# Declarign and intilizing sum variablearsum =0#Coping orignal value into a temp veriablet = num#While loop for iteration till t is greater than 0whilet >0:#if Yes#Applying Mo...
Python program to check Armstrong number using object oriented approach# Define a class for Checking Armstrong number class Check : # Constructor def __init__(self,number) : self.num = number # define a method for checking number is Armstrong or not def isArmstrong(self) : # copy num ...
python arm pythonArmstrongnumber Python基础练习之一输出10000以内的阿姆斯特朗数题目解析解题思路代码展示最后总结练习总结改进思考阿里云时间题目解析要解这道题,首先我们要清楚阿姆斯特朗数是什么意思;阿姆斯特朗数是说如果一个n位正整数等于其各位数字的n次方之和,则称该数为阿姆斯特朗数。比如13 + 53 + 33 = 153,14...
Armstrong number in C or Narcissistic number is an n-digit number equal to the sum of digits raised to the nth power of digits
Armstrong Number not Found between the Given Interval. Program to print Armstrong numbers between a range in Java importjava.util.Scanner;publicclassGenerateArmstrongNumber{publicstaticvoidmain(Stringargs[]){intn,n1,n2,i,rem,temp,count=0;Scanner scan=newScanner(System.in);/* enter the interval ...