# Python program to check if the number provided by the user is an Armstrong number or not # take input from the user num = int(input("Enter a number: ")) # initialize sum sum = 0 # find the sum of the cube of each digit temp = num while temp > 0: digit = temp % 10 sum...
So it will execute themethod code block, where we’ve initialized thevariable to get the number of digits in the number, like this:digit_count = len(str(num)). Then, we call the is_armstrong() method, which takes two parameters for number and digit_count:is_armstrong(num, digit_count...
以下是一个Python函数,用于检查一个n位数是否为Armstrong数: 代码语言:txt 复制 def is_armstrong_number(number): # 将数字转换为字符串以便逐位处理 num_str = str(number) n = len(num_str) # 获取数字的位数 # 计算各位数字的n次方之和 sum_of_powers = sum(int(digit) ** n for digit in num...
Python program to check ifthe number provided by the userisan Armstrong numberornot # take input from the user num = int(input("Enter a number: ")) # initialise sum sum =0 # find the sum of the cube of each digit temp = num whiletemp >0: digit = temp %10 sum += digit **3...
Python 提供了多种方法来检查一个字符是否为数字。本文将详细介绍在 Python 中检查字符是否为数字的几种...
实例(Python 3.0+) # Filename :test.py # author by : www.runoob.com # 获取用户输入数字 lower = int(input("最小值: ")) upper = int(input("最大值: ")) for num in range(lower,upper + 1): # 初始化 sum sum = 0 # 指数 n = len(str(num)) # 检测 temp = num while temp ...
Python program to check Armstrong number using object oriented approach# Define a class for Checking Armstrong number class Check : # Constructor def __init__(self,number) : self.num = number # define a method for checking number is Armstrong or not def isArmstrong(self) : # copy num ...
In this tutorial, you will learn to write a python program to check whether a number is Armstrong number or not for 3 digits number aswell as N digit number. Check 3 Digit Armstrong Number #Python program to check 3 Digits Armstrong Number #Taking input from user num = int(input("Enter...
Return "Armstrong" if num is an Armstrong Number. Otherwise, return "Not Armstrong". 1 2 3 function checkArmstrongNumber(num) { } Check Code Share on: Did you find this article helpful?Our premium learning platform, created with over a decade of experience and thousands of feedbacks. ...
printf("\nNumber %d is armstrong number", num); } } getch(); } OUTPUT: Explanation: In this program, we have to find all Armstrong numbers between 1 and 1000. For this, we firstly initialize (sum = 0) and temp = num = 1. Then we apply modulus operator(%) and various other ope...