Java Copy示例2:用于检查输入数字是否为 Armstrong 的程序import java.util.Scanner; public class JavaExample { public static void main(String[] args) { int num, number, temp, total = 0; System.out.println("Ënter 3 Digit Number"); Scanner scanner = new Scanner(System.in); num = scanner....
We loop through each integer in this range and call isArmstrong() to check if it is an Armstrong number. isArmstrong Method: This method takes an integer as input and checks whether it is an Armstrong number. It counts the digits using String.valueOf(num).length(). It calculates the sum...
示例importjava.util.Scanner; public class ArmstrongBetweenTwoNumbers { public static void main(String args[]){ int num1, num2; Scanner sc = new Scanner(System.in); System.out.println("Enter the first number ::"); num1 = sc.nextInt(); System.out.println("Enter the second number ::"...
Implementation: ArmstrongNumbersBruteforceOpt.java Hash Approach - Divide At Impera There is another interesting idea of bruteforce approach improvement. Divide a number for two equal parts. In case of an odd N first part will be a bit longer. For example, if N=7, the number will be divide...
def is_armstrong(num): # 将数字转换为字符串,以便逐位处理 str_num = str(num) n = len(str_num) # 计算各位数字的n次方之和 sum_of_powers = sum(int(digit) ** n for digit in str_num) # 判断是否为Armstrong数字 return sum_of_powers == num def filter_armstrong_numbers(numbers): retu...
Return "Armstrong" if num is an Armstrong Number. Otherwise, return "Not Armstrong". 1 2 3 function checkArmstrongNumber(num) { } Check Code Share on: Did you find this article helpful?Our premium learning platform, created with over a decade of experience and thousands of feedbacks. ...
printf("\nNumber %d is armstrong number", num); } } getch(); } OUTPUT: Explanation: In this program, we have to find all Armstrong numbers between 1 and 1000. For this, we firstly initialize (sum = 0) and temp = num = 1. Then we apply modulus operator(%) and various other ope...
num,"is Armstrong") else : print(self.num,"is not Armstrong") # Driver code if __name__ == "__main__" : # input number num = 153 # make an object of Check class check_Armstrong = Check(num) # check_Armstrong object's method call check_Armstrong.isArmstrong() num = 127 ...
In themain()function, we created four variablesnum,rem,res,tmpthat are initialized with 0. Then we read an integer number from the user and checked the given number is Armstrong or not. After that, we printed the appropriate message on the console screen....
todayDate and due date < tomorrowDate))) set maxNumReadingTasks to 2 set currentNumReadingTasks to 0 set maxNumVideoTasks to 1 set currentNumVideoTasks to 0 set maxNumClassTasks to 1 set currentNumClassTasks to 0 set maxNumExerciseTasks to 3 set currentNumExerciseTasks to 0 set isIntervie...