展开整理得zw*+z*w=0,化为z/z*=-w/w*.由于z和z*的幅角相反,商的幅角等于幅角差,z和-z的幅角相差(pai),得到 2arg(z)=2arg(w)(+或-)(pai).这样就可以得到 arg(z)-arg(w)=正负(pai)/2
Answer to: Given : Arg(z) = 2\pi/3 and Arg(w) = \pi/2. Find Arg(zw). By signing up, you'll get thousands of step-by-step solutions to your homework...
展开整理得zw*+z*w=0,化为z/z*=-w/w*.由于z和z*的幅角相反,商的幅角等于幅角差,z和-z的幅角相差(pai),得到2arg(z)=2arg(w)(+或-)(pai).这样就可以得到arg(z)-arg(w)=正负(pai)/2 解析看不懂?免费查看同类题视频解析查看解答
Ifzandware two complex number such that|zw|=1andarg(z)–arg(w)=π2,then show that¯zw=−i. View Solution If z and we are two complex numbers such that|zw|=1andarg(z)−arg(w)=π2then show that¯zw=−i View Solution ...
解(1 argz=π/(4) 示由原点出发,且与实轴角为 π/(4) 射线,即z的辐角为 π/(4) 其模为任意正数 \(znx=π/(4)x|z=r. r为任意正数. 上述射线在w=z2映射下有 ||ω|=r^2|ngzw=2ar|z| ||w|=r2 flwl=r' 即 [argw=-. 这就是曲线 argz=π/(4) 在ω=z^2 映...
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| z | <= 1, | w | <= 1, then show that | zw | ^ (2) <= (| z | - | w |) ^ (2) + (argz-argw) ^ (2) View Solution Let z and omega be two complex numbers such that |z|<=1,| omega|<=1 and |z+omega|=|z-1vec omega|=2 Use the result |z|^(2)=zz an...
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After washing, the cells were treated with 100 nM LysoTracker for 30 min, and confocal images were obtained using a confocal laser microscope (LSM880, AxioObserver, C-Apochromat 40×/1.2 W Korr FCS M27, Carl Zeiss, Oberkochen, BW, Germany) (cRGD probes: ex. 633 nm, em. 638–759 nm,...