百度试题 结果1 题目7. Find the total area of the shaded parts of the rectangle.16 cm15 cm Answer:cm2 相关知识点: 试题来源: 解析 Area of squareArea of triangleTotal area of shaded parts 反馈 收藏
Except for the four vertices of the rectangle, all the other points are the midpoints of the sides. What is the area of the shaded part?相关知识点: 试题来源: 解析 20(cm)^2. 如图,长方形面积为40,除长方形四个顶点外,其余各点均为各边中点,阴影部分的面积是多少?反馈 收藏 ...
Area of shaded region = Area of rectangle Area of triangle= 48 12= 36 square mExample 2Find the area of the shaded region in the following figure.SolutionStep 1:Area of rectangle = l × w = 8 × 5 = 40 sq ft; Area of triangle = 1212 b h = 1212× 4 × 3 = 6 sq ft...
14.The area of a rectangle is the product of the lengths of two adjacent sides.长方形的面积是相邻两边的长的乘积。 15.A bend or curve, especially in a shoreline.弯曲,弓形弯曲或弓形,尤指海岸线 16.What fraction of the area of ABC is the area of the shaded part?阴影部分的面积除以ABC(角...
What is one quarter of a circle? A quarter circle results from slicing a circle (such as a pizza) into four equal pieces. A quarter circle represents one of those four pieces. Look at the diagram. The part of the circle shaded in green is a quarter circle. It is a wedge-shaped regi...
If we divide the rectangle into 4 different segments with the focal point where all triangles meet, we can see that the shaded part of each segment is equal to half of each segment. Therefore, we can conclude that the area of the shaded parts is equal to half the area of rectangle = ...
As is shown in the picture, the area of the rectangle ABCD is 60 square centimeters. EC = 2DE,BG = GC, What is the area of the shaded part? 答案 111相关推荐 1As is shown in the picture, the area of the rectangle ABCD is 60 square centimeters. EC = 2DE,BG = GC, What is the...
BEF相等 因为三角形HDG(BEF)斜边是5，根据勾股定理求出HG(EF)、DH(FB)分别是3、4.（3²+4²=5²）因为HGD(BEF)是直角三角形求出两个三角形HGD和BEF=3×4×½×2=12.DGEB是平行四边形，根据图给的信息得知面积为5×6=30.所以阴影面积等于30-12=18 解...
Using the variance, we can apply Chebyshev's inequality to compute an upper bound on the probability that the currently shaded surface (at depth t) is occluded:This "one-tailed" version of Chebyshev's inequality is valid for t > . If t m, p max = 1 and the surface is ful...
AE=8,AD=6 => DE=10 AB//DC => ∠EDG=∠AED => DH/DG=AE/DE,HG/DG=AD/DE => DH=4,HG=3 => HE=DE-DH=6 => S=HE*HG=6*3=18