https://leetcode.com/problems/projection-area-of-3d-shapes/ https://leetcode.com/problems/projection-area-of-3d-shapes/discuss/156726/C%2B%2BJavaPython-Straight-Forward https://leetcode.com/problems/projection-area-of-3d-shapes/discuss/156771/11-line-1-pass-Java-code-and-explanation-of-the-...
883 Projection Area of 3D Shapes 三维形体投影面积 Description: On a N * N grid, we place some 1 * 1 * 1 cubes that are axis-aligned with the x, y, and z axes. Each value v = grid[i][j] represents a tower of v cubes placed on top of grid cell (i, j). Now we view the...
Now we view the projection of these cubes onto the xy, yz, and zx planes. A projection is like a shadow, that maps our 3 dimensional figure to a 2 dimensional plane. Here, we are viewing the "shadow" when looking at the cubes from the top, the front, and the side. Return the t...
883. Projection Area of 3D Shapes* https://leetcode.com/problems/projection-area-of-3d-shapes/ 题目描述 On a N * N grid, we place some 1 * 1 * 1 cubes that are axis-aligned with the x, y, ...
883. Projection Area of 3D Shapes On a N * N grid, we place some 1 * 1 * 1 cubes that are axis-aligned with the x, y, and z axes. Each value v = grid[i][j] represents a tower of v cubes placed on top of grid cell (i, j)....
Here, we are viewing the shadow when looking at the cubesfrom the top, the front, and the side. Return the total area of all three projections. Example 1: Input: [[2]]Output: 5 Example 2: Input: [[1,2],[3,4]] Output: 17 Explanation: Here are the three projections ("shadows"...
Find the area of shapes in Maths here. Learn the formulas for the area of different types of plane figures and solid shapes along with the table and solved examples at BYJU'S.
// LeetCode 2020 easy #778 // 883. Projection Area of 3D Shapes // https://leetcode.com/problems/projection-area-of-3d-shapes/ // Runtime: 296 ms, faster than 5.76% of C++ online submissions for Pro…
883. Projection Area of 3D Shapes class Solution { public: int projectionArea(vector<vector<int>>& grid) { int a[1000]; memset(a, 0, sizeof(a)); int sum = 0; int howlong = 0; for (vector<vector<int>>::iterator it = grid.begin(); it != grid.end();...
After placing these cubes, you have decided to glue any directly adjacent cubes to each other, forming several irregular 3D shapes. Return the total surface area of the resulting shapes. Note: The bottom face of each shape counts toward its surface area. ...