当0≤x≤1时, are sinz 及 are cos x同属区间 (0,σ/(2)) ,因正弦函数 在此区间为增函数,对不等式两端取正弦,得 x=√(1-x^2) ,解得 (√2)/2a≤1 、 故原不等式的解为 (√2)/2x≤1 . [解二]在同一个平面直角坐标系上分别作函数 y=aresinz与 y=arccosω 的图象,得它们的交点坐 ...
选择恰当的单词,并用其适当的形式填空。 sin3▱=cos( 1. Are you your homework now? 2. I'm a picture. 3. My father is a book. 4. Grandma's birthday is . 5. He is Chinese. 相关知识点: 试题来源: 解析 1.doing;2.drawing;3.reading;4.coming;5.studying.【句意提示】 1. 你现在...
Find sin A. Find the exact trigonometric function value \sin 2385^{\circ} (a) \frac{-\sqrt{2{2} (b) 2\sqrt{3} (c) \frac{-\sqrt{3{2} (d) \frac{-1}{2} Solve the following problem: For 0 = \sin c^{-1}(\frac{a...
The correct Answer is:D To solve the problem, we need to find the value of α such that the functions sin(αx)+cos(αx) and |cosx|+|sinx| have the same fundamental period. 1. Determine the Period of sin(αx)+cos(αx): - The period of sinx and cosx is 2π. - For sin(α...
sin(θ) cosine adj/hyp cos(θ) tangent opp/adj tan(θ) name ratio notation cosecant hyp/opp csc(θ) secant hyp/adj sec(θ) cotangent adj/opp cot(θ) The ratios sine, cosine, and tangent are the "regular" trig ratios; the cosecant, secant, and cotangent are their respective reciproc...
【解析】 [分析],反三角函数是一个角(或弧)对应的实数,故可先设arcsinx= A.则$$ \sin A = x a r c \cos t g A = B $$,可得$$ \cos B = t g A $$,再求sinB.按此从里向外逐段简化即可。 [解] 设$$ a r e g i n x = A $$,则$$ \sin A = x $$,且$$ A \in ...
(1)I draw a picture for my story.(2)I read a book.(3)I sing a song with my friends.(4)I do my homework in the evening.(5)What do you do in the evening?(1)【句意】我为了我的故事画了一张画。【知识点拨】本题考查陈述句。【分析】由“.”可知本题是陈述句,故将I放于句首,后...
The sine of one of the angles of a right triangle (often abbreviated “sin”) is the ratio of the length of the side of the triangle opposite the angle to the length of the triangle’s hypotenuse. The cosine (often abbreviated “cos”) is the ratio of the length of the side adjacent...
If sintheta and costheta are the roots of the equation ax^2-bx+c=0, then a, b and c satisfy the relation
the azimuth angles21float3 E_p = normalize(EyeVect-NdotE*Normal);22float3 L_p = normalize(LightDir-NdotL*Normal);23floatcosAzimuth =dot(E_p, L_p);24//Compute final lighting25floatinten = rho_pi * cosTheta_i *26(A + B * max(0, cosAzimuth) *27max(sinTheta_r, sinTheta_i) ...