百度试题 结果1 题目 Approximate the sum of each series to the indicated level of accuracy:∑_(n=1)^∞((-1)^(n+1))/(n!)(cmor0.011) 相关知识点: 试题来源: 解析 S_4=0.625 反馈 收藏
The sum of a series can be approximated by adding sufficient number of terms of the series. The number of terms depends on the desired accuracy of the sum - higher accuracy general requires higher number of terms. Answer and Explanation: The nth term of the ...
Approximate the sum of the series ∑n = 1∞(−1)n9n n! correctly to 4 decimal places. Sum of a Series: The sum of the series that has the general expansion is formed using the expansion formula. Th expansion formula used in the given problem is for t...
百度试题 结果1 题目Approximate the sum of the series correct to four decimal places.∑_(n=1)^∞(-1)^nne^(-2n) 相关知识点: 试题来源: 解析 -0.1050 反馈 收藏
reckon,count- take account of; "You have to reckon with our opponents"; "Count on the monsoon" truncate- approximate by ignoring all terms beyond a chosen one; "truncate a series" guesstimate- estimate based on a calculation Adj.1.approximate- not quite exact or correct; "the approximate ...
|R_N| ≤ a_(N+1)=1((N+1)^4).For an error of less than 0.001, N must satisfy the inequality 1/(N+1)^4 < 0.001.1/(N+1)^4 < 0.001So, you will need at least five terms. Using five terms, the sum is 1/(N+1)^4 < 0.001, which has an error of less than 0.001. ...
An approximate formula for a partial sum of the divergent p-series. Applied Mathematics Letters, 22 (5):732-737, 2009.E. Chlebus, An approximate formula for a partial sum of the divergent p-series, Appl. Math. Lett., 22(2009) 732-737....
reckon,count- take account of; "You have to reckon with our opponents"; "Count on the monsoon" truncate- approximate by ignoring all terms beyond a chosen one; "truncate a series" guesstimate- estimate based on a calculation Adj.1.approximate- not quite exact or correct; "the approximate ...
结果1 题目 Use the sum of the first 10 terms to approximate the sum of the series. Estimate the error.∑limits _(n=1)^(∞ ) 1(√ (n^4+1)) ___ 相关知识点: 试题来源: 解析 ∑limits ^(10)_(n=1) 1(√ (n^4+1))≈ 1.24856. 反馈 收藏 ...
Approximate the value of the series to within an error of at most104. ∑n=1∞(-1)n+1(n+79)(n+74) According to Equation(2): |SN-S|≤aN+1 what is the smallest value ofNthat approximatesSto within an error of at most10-4?