PE7AP412-01由PASTERNACK设计生产,立创商城现货销售。PE7AP412-01价格参考￥636.81。PASTERNACK PE7AP412-01参数名称:频率范围:0Hz~40GHz;阻抗:50Ω;衰减值:1dB。下载PE7AP412-01中文资料、引脚图、Datasheet数据手册,有RF衰减器详细引脚图及功能的应用电路图电压和
(2013•廊坊一模)如图1,将一个直角三角板的直角顶点P放在正方形ABCD的对角线BD上滑动,并使其一条直角边始终经过点A,另一条直角边与BC相交于点E. (1)求证:PA=PE; (2)若将(1)中的正方形变为矩形,其余条件不变(如图2),且AD=10,DC=8,求AP:PE; ...
PE and QE b Assume that the noise from the fireworks disturbs all of the neighbors On your graph in part a show each of the following i The marginal social cost curve labeled MSC ii The marginal social benefit curve labeled MSB iii The deadweight loss if any shaded completely c Now ...
9.如图,在梯形ABCD中,AD∥BC,∠A=90°,AB=6,BC=10,AD=7,点P在边AD上运动(不与点A,D重合),E是边AB上一点,连结PC,PE,EC. (1)当点B,P关于直线EC对称时,求BE的长; (2)设BE=a,若存在唯一点P,使∠EPC=90°,求a,AP的值. 试题答案 ...
Le certificat auto-signé n'est pas approuvé pendant et après une mise à niveau de 8.0 Platform Edition (PE) vers 8.1 Enterprise Edition (EE) UR2. (ID 6296105) Supprimez les entrées suivantes de la cible domain.xml (après la mise à niveau) et redémarrez le serveur : <jvm-optio...
Curriculum 2013 is a curriculum that prioritizes understanding, skills, and character education, students are required to understand the material, active in discussions and presentations and have a high discipline manners. In the 2013 curriculum, the division of departments through junior high school gr...
ASZ001 cells were grown in 6-well plates, then serum starved for 24 h and treated with 5 ng/ml TGFß3 (Peprotech), 10 µM ALK5 inhibitor SB431542 (SelleckChem), and/or 20 µM AP-1 inhibitor T-5224 (SelleckChem). NIH-3T3 cells were transiently transfected with ...
操作与证明:如图1,已知P是矩形ABCD的边BC上的一个点(P与B、C两点不重合),过点P作射线PE⊥AP,在射线PE上截取线段PF,使得PF=AP.(1)过点F作FG⊥BC交射线BC点G.(尺规作图,保留痕迹,
Insan, Media Psikologi, 15 (1), 54-62.Zulkarnain dan Annisa. 2013. Komitmen terhadap Organisasi ditinjau dari Kesejahteraan Psikologis Pekerja. Insan. Vol. 15. No. 01. Hal. 54-62. Sumatera: Departemen Psikologi Industri dan Organisasi Fakultas Psikologi Universitas Sumatera Utara....
【题目】如图1,在正方形ABCD中,P是对角线BD上的一点,点E在AD的延长线上,且PA=PE,PE交CD于F.(1)证明:PC=PE;(2)求∠CPE的度数;(3)如图2,把正方形ABCD改为菱形ABCD,其他条件不变,当∠ABC=120°时,连接CE,试探究线段AP与线段CE的数量关系,并说明理由....