const aa=newA(); interface 是会直接被保护的,但是 class 不会, 如果希望行为一致那么就要开启 strictPropertyInitialization. 那么 class 就需要放入初始值了. 这也符合 c# 的方式,挺好的. 但是面对 angular 的话, 比如 @Input 你可能不希望它检查. 那么可以 age! 加叹号在属性后面来做断言 更新: 2019-12-2...
解决办法 打开angular工程中的tsconfig.json文件,在“compilerOptions”中添加:"strictPropertyInitialization": false //tsconfig.json "compilerOptions":{ ... "strictPropertyInitialization": false, ... } 添加属性初始化约束为false发布于 2022-04-11 22:04 Angular ...
// "strictNullChecks": true, /* Enable strict null checks. */ // "strictFunctionTypes": true, /* Enable strict checking of function types. */ // "strictPropertyInitialization": true, /* Enable strict checking of property initialization in classes. */ // "noImplicitThis": true, /* Ra...
{ selector: '...', templateUrl: '...html', styleUrls: ['...css'],})export class MyComponent implements OnInit { @ViewChild(myDirective) directive; ngOnInit() { } onClickFunction() { return ( this.directive?.myMethod() ); }} 在tsconfig.json中添加 "strictPropertyInitialization":false...
说是属性没有在构造器里面初始化。但是每个类每个属性都要初始化的话太麻烦了。 TypeScript官方文档中查到了方法,可以关闭这个检查: https://www.typescriptlang.org/docs/handbook/release-notes/typescript-2-7.html 方法:tsconfig.json > compilerOptions, 增加一项:"strictPropertyInitialization":false, 这样就能...
{ selector: '...', templateUrl: '...html', styleUrls: ['...css'],})export class MyComponent implements OnInit { @ViewChild(myDirective) directive; ngOnInit() { } onClickFunction() { return ( this.directive?.myMethod() ); }} 在tsconfig.json中添加 "strictPropertyInitialization":false...
Development Setup Prerequisites InstallNode.jswhich includesNode Package Manager Setting Up a Project Install the Angular CLI globally: npminstall-g@angular/cli Create workspace: ngnew[PROJECT NAME] Run the application: cd[PROJECT NAME] ng serve ...
typescript 2.7 strict property initialization breaks type inference Closed JeklahcommentedMar 4, 2019 I got this today with a simple where 'search' was undefined and was giving me red squiggles. App compiled and worked as intended (to my frustration after spending half the day trying to ...
If migrating to typed forms, update the form property initialization to use typed controls, which will provide better type inference and catch potential errors at compile-time. Example of future typed form (not to be implemented now): form = this.fb.group({ value: ['', [Validators.required...
有吸引力得多，因为：它很简短具备 TypeScript 自动类型推断支持满足 TypeScriptstrictPropertyInitialization...