题意:找最近的公共祖先; 思路:关键是函数的定义:lowestCommonAncestor()就是可以给你返回你的最近公共祖先;然后利用后根遍历进行递归;
p,q);TreeNode right=lowestCommonAncestor(root.right,p,q);if(left!=null&&right!=null){returnroot;}if(left!=null){returnleft;}if(right!=null){returnright;}returnnull;}}
给的是BST(无相同节点),那么每个节点肯定大于左子树中的最大,小于右子树种的最小。根据这个特性,找LCA就简单多了。 分三种情况: (1)p和q都在root左边,那么往root左子树递归。 (2)在右同理。 (3)一左一右的,那么root->val肯定大于其中的1个,小于另一个。 AC代码 python3 迭代 AC代码 递归 AC代码...
Given a binary tree, find the lowest common ancestor (LCA) of two given nodes in the tree. According to thedefinition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow...
leetcode 236 二叉树的最近公共祖先 lowest-common-ancestor-of-a-binary-tree【ct】,思路:1构造一个map,map的keyvalue对应节点和它的父节点2构造一个set,对于p,向上找,记录它到父节点所有的节点3.对于q,向上找,如果set中包含这个节点,那么这个节点就是公共节点,
1.Tracing Back to Ancestors: A Comparative Analysis on Family Tree of Jiang Clan in Fujian and Taiwan;追寻祖先:闽台《江氏族谱》的比较分析 2.Holding that everything has a soul,the Miao people think that the Chinese sweet gum tree,the peacock family,Pan Hu,Mother Butterfly,and Jangb Vangb ...
public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) { if (root == null) { return root; } if (root.val > Math.max(p.val, q.val)) { return lowestCommonAncestor(root.left, p, q); } else if (root.val < Math.min(p.val, q.val)) { ...
Australopithecines that have been considered ancestral in the lineage leading to the human genusHomoincludeA. afarensis(an important skeleton of which is popularly known as Lucy) andA. africanus.The exact position of these and other early species on the hominin family tree continues to be ...
采用递归,分别在左子树和右子树里面查找,如果都能找到,当前节点就是最近共同祖先 如果只能在一个树找到,说明这个数就是最近共同祖先 structTreeNode*lowestCommonAncestor(structTreeNode*root,structTreeNode*p,structTreeNode*q){if(root==NULL||root==p||root==q)returnroot;structTreeNode*left=lowestCommonAncest...