import java.util.Scanner; public class Solution { static boolean isAnagram(String a, String b) { boolean x= true; if (a.length()!=b.length()){ x=false; } a= a.toLowerCase(); b=b.toLowerCase(); int al[]=new int [256]; for(char c : a.toCharArray()){ int i=(int) c;...
public static boolean isAnagram(String a,String b) { char a1[]=a.toCharArray(); char b1[]=b.toCharArray(); java.util.Arrays.sort(a1); java.util.Arrays.sort(b1);
import java.util.Scanner; public class Solution { static boolean isAnagram(String a, String b) { boolean x= true; if (a.length()!=b.length()){ x=false; } a= a.toLowerCase(); b=b.toLowerCase(); int al[]=new int [256]; for(char c : a.toCharArray()){ int i=(int) c;...
import java.util.Scanner; public class Solution { static boolean isAnagram(String a, String b) { boolean x= true; if (a.length()!=b.length()){ x=false; } a= a.toLowerCase(); b=b.toLowerCase(); int al[]=new int [256]; for(char c : a.toCharArray()){ int i=(int) c;...
public class Solution { static boolean isAnagram(String a, String b) { // Complete the function a = a.toLowerCase(); b = b.toLowerCase(); boolean anagram = true; if (b.length() == a.length()) { java.util.Map amap = new java.util.HashMap<>(); java.util.Map bmap = new ...
Java AnagramsProblem Submissions Leaderboard Discussions Editorial You are viewing a single comment's thread. Return to all comments → sguptayaman584 4 years ago updated solution is here https://www.thecscience.com/2021/05/HackerRank-java-anagrams-problem-solution.html -4|ParentPermalinkBlog...
here is solution of problem Java Anagrams https://programs.programmingoneonone.com/2021/02/hackerrank-java-anagrams-solution.html -84|ParentPermalink kaarthik_s73 5 years ago Really? After all that stuff on time complexity, you are posting this? 0|ParentPermalink ofbuyukbas 4 years ago First ...
Java Anagrams I dont see how this solution takes into consideration a word that has the same amount of letters as string A, has all the same letters but a different frequency of a certain letter. For example hello and heelo are not anagrams...
Java Anagrams In this case, I have to search each character in the first string in the second string. I was thinking to use HashMaps at first, but, I realized, I can't do that here. So, I came up with this solution: static boolean isAnagram(String a, String b) {...
Java Anagrams Can someone help me please? Solution.java:19: error: cannot find symbol Map map = new HashMap<>(); ^ symbol: class Map location: class Solution Solution.java:19: error: cannot find symbol Map map = new HashMap<>(); ^ symbol: class HashMap location: class Solution 2 ...