首先对每个string转换成char array然后排下序,HashMap里面的key存sort后的词,value存原始的词。然后如果这个排好序的词没在HashMap中出现过,那么就把这个sorted word和unsortedword put进HashMap里面。如果一个sorted word是在HashMap里面存在过的,说明这个词肯定是个变形词,除了把这个词加入到返回结果中,还需要把之...
Java Anagrams问题 问题描述 Anagrams指的是具有如下特性的两个单词:在这两个单词当中,每一个英文字母(不区分大小写)所出现的次数都是相同的。例如,“Unclear”和“Nuclear”、“Rimon”和“MinOR”都是Anagrams。编写一个程序,输入两个单词,然后判断一下,这两个单词是否是Anagrams。每......
Given an array of strings, return all groups of strings that are anagrams. Note: All inputs will be in lower-case. 思路: anagrams是变化词,string中字符变化,形成新的string。则所有的angrams中字符相同,字符个数相同 所以需要判断是否是anagrams,用排序。mlogm,并且遍历n。 java 代码: public List<Str...
Write a Java program to find all the start indices of a given string's anagrams in another given string.Visual Presentation:Sample Solution:Java Code:// Importing necessary Java utilities import java.util.*; // Main class public class Main { // Main method public static void main(String[] ...
Java Anagrams import java.util.Scanner; public class Solution { static boolean isAnagram(String a, String b) { boolean x= true; if (a.length()!=b.length()){ x=false; } a= a.toLowerCase(); b=b.toLowerCase(); int al[]=new int [256];...
[leetcode]49. Group Anagrams Analysis 直男真可怕—— [每天刷题并不难0.0] Given an array of strings, group anagrams together. Explanation: 用hashtable实现~ Implement 蓝桥杯算法训练_2的次幂表示+前缀表达式+Anagrams问题+出现次数最多的整数 存放两个字符串,将英文字母在字母表中的顺序对应数组的下标,...
LeetCode Top 100 Liked Questions 49. Group Anagrams (Java版; Medium) 题目描述 Given an array of strings, group anagrams together. Example: Input: ["eat", "tea", "tan", "ate", "nat", "bat"], Output: [ ["ate","eat","tea"], ...
leetcode 49 Group Anagrams 题目详情 Given an array of strings, group anagrams together. 题目要求输入一个字符串数组,我们要将由同样字母组成的字符串整理到一起,然后以如下例子中的格式输出。 不需要关注输出的顺序,所有的输入都是小写。 Example:
Given a string s and a non-empty string p, find all the start indices of p's anagrams in s. Strings consists of lowercase English letters only and the length of both strings s and p will not be larger than 20,100. The order of output does not matter. ...
CAN YOU HELP ME OUT, THIS CODE IS FAILED WITH INPUT Hello,hello ; expected output:anagram ; actual : not anagram; public static boolean isAnagram(String a,String b) { char a1[]=a.toCharArray(); char b1[]=b.toCharArray(); java.util.Arrays.sort(a1); java.util.Arrays.sort(b1);...